I'm just going to number all of the problems so life get's easier. :D
JSYK: A negative and a negative multiplied make a positive. Like that... a + and a + is +. And a + and a - is a - .
1) 37= -3+5(k+6)
1. Use Distributive Property to take out the parentheses. Positive 5 times k and then 5 times 6... 37=-3+5k+30. 2. Take all the normal number to either side of the equal sign. 37-3-30=5k 3. Subtract all the numbers on the left side.... 4=5k 4. Now divide both sides by 5 to isolate <em>k</em>.... k=[tex] \frac{4}{5} [/text] ----------------------------------------------------------------------------------------------- 2) -2= -(w-8)
1. Use Distributive Property to take out the parentheses. "Distribute the negative sign... -2= -w+8 2. Put the -w to the left side and the -2 to the right side, so that the variable won't be negative... w= 2+8 3. Add everything on the right side... w= 10 ----------------------------------------------------------------------------------- 3) 42= 8x+13x
1. Since both of the numbers have the same variables (in this case, x), add them up... 42=21x 2. Divide each side by 21 to isolate <em>x</em>... x=42 ------------------------------------------------------------------------------------ 4) 8= 8c-4(c+8)
1. Use Distributive Property. Multiply <em>negative</em> 4 with c and 8... 8=8c-4c-32 2. On the right side, 8 and 4 both have the same variable, <em>c </em>, solve it!...8=4c-32 3. Put -32 to the left side... 8+32=4c 4. Add on the left... 40=4c 5. Divide both sides by 4 to isolate <em>c</em>... c=10 ------------------------------------------------------------------------------------- 5) -11-5z= 6(5z+4) 1. Use Distributive Property; multiply positive 6 with 5z and 4... -11-5z=30z+24 2. Bring -5z to the right and positive 24 to the left... -11-24= 30z+5z 3. Subtract the integers on the left and add the numbers with same variable on the right... -35=35z 4. Divide both sides by 35 to isolate <em>z</em>... z= -1 ----------------------------------------------------------------------------- 6) 0= -5y-2y
1. Subtract the negative number with the same variable, <em>y</em> ... 0= -7y 2. Divide both sides by -7, to isolate <em>y</em>... y=0
And for the last two, I don't know either... my apologies! I hope my answers help! :D
Answer:
1. ∠LOQ = 80°
2. ∠LRQ = 40°
3. ∠LBQ = 40°
Step-by-step explanation:
- The measure of a central angle (angle that goes to the center of the circle) is EQUAL to the ARC from which it is intercepted.
- The measure of the angle that is on opposite side, on the circumference, of the circle is HALF of the ARC from which it is intercepted.
It is given that ARC QL has a measure of 80.
- Central angle from ARC QL (with same measure) are angle LOQ only.
- Opposite angles (half of measure of ARC QL) from ARC QL (on opposite side on circumference) are angles LRQ and LBQ.
<u>1.</u>
m∠LOQ: ∠LOQ is the central angle from ARC QL so it has SAME MEASURE.
∠LOQ = 80°
<u>2.</u>
m∠LRQ: ∠LRQ is the opposite angle from ARC QL so it is HALF of ARC QL.
∠LRQ = 
∠LRQ = 40°
<u>3.</u>
m∠LBQ: ∠LBQ is also another opposite angle from ARC QL so it is HALF of ARC QL as well.
∠LBQ = 
∠LBQ = 40°
Answer:
seven
Step-by-step explanation:
Lol thxx for the points
Pls give brainliest! Also, plz sub to kgirl633 on yt.
Factor by grouping
<span> 5x^2 - 34x + 24
= (x-6)(5x-4)</span>
Answer:
Half of a number is 15
Step-by-step explanation:
First of all, add commas between each option so it's easier to read I had a hard time figuring out what the options were because of this.
An equation is a statement that the values of two mathematical expressions are equal. An expression is a collection of symbols that jointly express a quantity. This means there has to be an equal sign when the phrases are put into numerical form.
Twice as much as a number: 2X
12 less than a number: X - 12
Half of a number is 15: X/2 = 15
The difference of 20 and a number: 20 - X
As you can see, only one of these phrases is an equation by definition, and that is X/2 = 15, or half of a number is 15. That's because it's the only one that values two expressions as equal.