11. You’ve done it correctly
12. Let x^2=y
y^2+13y+40=0
(y+8)(y+5)=0
y=8, 5
Since y=x^2
x^2=8 x^2=5
x=+/-√5 x= +/-2√2
13. x^4-x^2-x^2-8=0
x^4-2x^2-8=0
let x^2=y
Y^2-2y-8=0
(y-4)(y+2)=0
y=4, -2
Since y=x^2
X^2=4 X^2=-2
X= +/- 2 This wouldn’t be a real solution
14. It’s pretty much the same process, just substitute y in for x^2. If you’re confused feel free to ask and I can do it, or you can put it through Photomath
15. You’re on the right track so I’m just going to continue from where you left off
x^2(4x+5)-4(x+5)=0
(x^2-4)(4x+5)=0
x= +/- 2 4x=5
x=5/4 or 1 1/4
Hope this helped :)
You add $5.38 & $15.95, which equals $21.33. Then subtract $21.33 from $38.12. Your answer is $16.79. That's how much Shane spent on the book.
Since this is a 45-45-90 right triangle, the hypotenuse = sqrt2 * leg
24 is the hypotenuse so we need to find the leg.
24 = sqrt2 * leg
Divide both sides by sqrt2
leg = 16.97
A = (1/2)b*h
A = (1/2)*16.97*16.97
A = 144ft^2
For the a factor in a 1 and then do the problem once you find the product plug your a back in
<h2>
<u>A</u><u> </u><u>N</u><u> </u><u>S</u><u> </u><u>W</u><u> </u><u>E</u><u> </u><u>R</u><u> </u><u>:</u></h2>
- Perimeter of rectangle = 40 inches
- Length of rectangle = 15 inches
Let the required Breadth of rectangle be 'x' inches
Perimeter of rectangle is calculated by the given below formula :
- Perimeter = 2(Length + Breadth)
Now, substitute the given values in above formula :
→ 40 = 2(15 + x)
<u>Hence</u><u>,</u><u>the</u><u> </u><u>optio</u><u>n</u><u> </u><u>(</u><u>d</u><u>)</u><u> </u><u>2</u><u>(</u><u>x</u><u> </u><u>+</u><u> </u><u>1</u><u>5</u><u>)</u><u> </u><u>=</u><u> </u><u>4</u><u>0</u><u> </u><u>is</u><u> </u><u>the</u><u> </u><u>corre</u><u>ct</u><u> </u><u>answer</u><u>.</u>