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tiny-mole [99]
3 years ago
15

ABC IS a right angled triangle at B and D is a point on BC. If AD=18cm , BD=9cm and CD = 4 cm, find AC

Mathematics
1 answer:
leva [86]3 years ago
4 0
AB =  \sqrt{ AD^{2} - BD^{2} } =  \sqrt{243} = 9 \sqrt{3} 

AC = \sqrt{ AB^{2} + BC^{2} } =  \sqrt{412} = 2 \sqrt{103}
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Find the length of a leg of an isosceles right triangle whose hypotenuse measures 8√2
Maslowich
The length the hypotenuse of an isosceles right triangle, or a 45-45-90 triangle, is always radical two times as long as any leg of the triangle. With this, we can set up an equation where x represents the length of a leg.

x\sqrt{2} = 8\sqrt{2}
divide both sides by \sqrt{2} 
x = 8

The length of a leg of the triangle is 8 
8 0
3 years ago
Recall from Example 1 that whenever Suzan sees a bag of marbles, she grabs a handful at random. She has seen a bag containing th
hammer [34]

Answer:

Required Probability in the lowest terms as fractions =  \frac{15}{182} =0.0824

Step-by-step explanation:

Step 1:-

Given Suzan has three red marbles, two green ones, five white ones, and two purple ones.

Total marbles = 3R+2G+5W+2P = 12

The number of exhaustive cases that the five marbles drawn from 12 marbles

n(S) = 12C_{5} = 792 ways

by using formula n_{Cr_{} } = \frac{n!}{(n-r)!r!} = \frac{12!}{(12-5)!5!}   = 792

The number of favorable cases

She has drawn two red marbles from 3 red marbles, that is 3c₂ ways

she has drawn one  marble drawn from 2 green marbles, that is 2c₁ ways

she has drawn one  marble drawn from 5 white marbles, that is 5c₁ ways

she has drawn one  marble drawn from 2 purple marbles, that is 2c₁ ways

The favorable cases are (n(E) = 3c₂ X 2c₁X5c₁X2c₁ = 60 ways

Required Probability = \frac{n(E)}{n(S)}

Required  probability = \frac{n(E)}{n(S)} = \frac{60}{792}

Required Probability in the lowest terms as fractions =  \frac{15}{182} =0.0824

3 0
3 years ago
Find dy/dx by differentiating implicitly <br> x^2y+3xy^3-x=3
AleksandrR [38]
\dfrac{\mathrm d}{\mathrm dx}\left[x^2y+3xy^3-x\right]=\dfrac{\mathrm d}{\mathrm dx}[3]
2xy+x^2\dfrac{\mathrm dy}{\mathrm dx}+3y^3+9xy^2\dfrac{\mathrm dy}{\mathrm dx}-1=0
(x^2+9xy^2)\dfrac{\mathrm dy}{\mathrm dx}=1-2xy-3y^3
\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{1-2xy-3y^3}{x^2+9xy^2}
6 0
3 years ago
40 is 4 times as many as 10<br> True or false
DerKrebs [107]

Answer:

<h2>true</h2>

Step-by-step explanation:

4 x 10= 40 so true

6 0
3 years ago
Read 2 more answers
Pwaseee help:)))))))
viktelen [127]

If you divide both sides by -4 you'll get:

-10x -12

7 0
3 years ago
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