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tiny-mole [99]
3 years ago
15

ABC IS a right angled triangle at B and D is a point on BC. If AD=18cm , BD=9cm and CD = 4 cm, find AC

Mathematics
1 answer:
leva [86]3 years ago
4 0
AB =  \sqrt{ AD^{2} - BD^{2} } =  \sqrt{243} = 9 \sqrt{3} 

AC = \sqrt{ AB^{2} + BC^{2} } =  \sqrt{412} = 2 \sqrt{103}
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The sum of 5 consecutive numbers is -5. What is the largest out of the numbers?
xxTIMURxx [149]
We can say that x is the largest number.

So the sum is x + (x - 1) + (x - 2) + (x - 3) + (x - 4) = -5

Now solve for x:

x + x + x + x + x - 1 - 2 - 3 - 4 = -5

5x - 10 = -5

5x = 5

x = 1

So the largest number is 1.

Check: 1 + 0 + -1 + -2 + -3   =   -2 + -3   =   -5 so 1 is correct.
3 0
3 years ago
Randy saving for console cost $290 he got a $50 gift card from grandma $15 each week, how many weeks until he get money?
aalyn [17]

Answer:

it will take him 16 weeks

Step-by-step explanation:

290 subtract 50 equals 240

240 divided by 15 equals 16

7 0
3 years ago
What is the area of a 14m by 5m rectangle?
Lisa [10]
Area=L multiply by W
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7 0
3 years ago
Which set of coefficients of the terms in the expansion of the binomial (x+y)^3 is correct ?
BigorU [14]
We are technically FOILing this out... with a power of 3.

(x+y)(x+y)(x+y)

So we can first factor out the first two "x+y"s.

( x^{2} +2xy + y^{2} ), multiplied by the last "x+y".

x^{3} +3 x^{2} y +3x y^{2} + y^{3}

Coefficients are the number that comes in front of a variable. 

In this case, 1 comes in front of x^{3}, 3 comes in front of x^{2} y, 3 comes in front of x y^{2}, and 1 comes in front of y^{3}.

Thus: 1, 3, 3, 1.
         Answer Choice A
4 0
3 years ago
Read 2 more answers
Find 1+ 2+ 3+ 4+ ... +50, the sum of the first 50 natural numbers.<br> The sum is
SOVA2 [1]

Step-by-step explanation:

First term(a) = 1

Common difference(d)=2-1=1

No.of term(n)=50

Sn=n÷2(n+1)=50÷2(50+1)=1275

7 0
3 years ago
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