NaOH but you didnt give options
Answer:
The value of entropy change for the process 
Explanation:
Mass of the ideal gas = 0.0027 kilo mol
Initial volume
= 4 L
Final volume
= 6 L
Gas constant for this ideal gas ( R ) = 
Where
= Universal gas constant = 8.314 
⇒ Gas constant R = 8.314 × 0.0027 = 0.0224 
Entropy change at constant temperature is given by,

Put all the values in above formula we get,
![dS = 0.0224 log _{e} [\frac{6}{4}]](https://tex.z-dn.net/?f=dS%20%3D%200.0224%20%20log%20_%7Be%7D%20%5B%5Cfrac%7B6%7D%7B4%7D%5D)
This is the value of entropy change for the process.
Answer: The answer is 6.78 grams.
Explanation: The equation used for solving this type of problems is:

where,
is the initial amount of radioactive substance, N is the remaining amount and n is the number of half lives.
Number of half lives is calculated on dividing the given time by the half life.
n = time/half life
Time is given as 48.0 hours and the half life is given as 4.536 days. let's make the units same and for this let's convert the half life from days to hours.

= 108.864 hours
So,
= 0.441
Since 5.00 g is the required amount when the radioactive substance is delivered to the scientist, it would be the final amount that is N. We need to calculate the initial amount. Let's plug in the values in the equation:



= 6.78 g
So, 6.78 g of the radioactive substance needs to be ordered.