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beks73 [17]
3 years ago
8

Help me number 6 and 7 please

Chemistry
1 answer:
Doss [256]3 years ago
7 0
Answer : 6 - b And 7 - d
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Lady_Fox [76]

Answer:

Kinetic

Explanation:

Kinetic energy kicks in after potienal builds up energy

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3 years ago
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Do moles of any substance have the same number of atoms
love history [14]
The term mole refers to 6.02x10²³ atoms or molecules of any substance. so regardless of the substance one mole will always be equivalent to 6.02x10²³

Hope that helps 
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3 years ago
In a cathode ray tube, the number of electrons that reach the fluorescent screen is controlled by the
lutik1710 [3]
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The cathode serves as the positive terminal and the anode as the negative terminal. The flow of electrons is from the cathode to the anode.</span><span>The relationship between a cathode and an anode involves electrons. An example of this is reaction that takes place in an electrolytic cell. It has a cathode compartment, an anode compartment and a salt bridge that divides the compartment. The movement of electrons is from the cathode to the anode. </span>
7 0
4 years ago
Assuming complete dissociation of the solute, how many grams of KNO3 must be added to 275 mL of water to produce a solution that
iragen [17]

Answer:

108.43 grams KNO₃

Explanation:

To solve this problem we use the formula:

  • ΔT = Kf * b * i

Where

  • ΔT is the temperature difference (14.5 K)
  • Kf is the cryoscopic constant (1.86 K·m⁻¹)
  • b is the molality of the solution (moles KNO₃ per kg of water)
  • and<em> i</em> is the van't Hoff factor (2 for KNO₃)

We <u>solve for b</u>:

  • 14.5 K = 1.86 K·m⁻¹ * b * 2
  • b = 3.90 m

Using the given volume of water and its density (aprx. 1 g/mL) we <u>calculate the necessary moles of KNO₃</u>:

  • 275 mL water ≅ 275 g water
  • 275 g /1000 = 0.275 kg
  • moles KNO₃ = molality * kg water = 3.90 * 0.275
  • moles KNO₃ = 1.0725 moles KNO₃

Finally we <u>convert KNO₃ moles to grams</u>, using its molecular weight:

  • 1.0725 moles KNO₃ * 101.103 g/mol = 108.43 grams KNO₃
5 0
3 years ago
Complete and balance the following equation:
sertanlavr [38]
You need to add the last substance to the products side(the right sode of the arrow). You have hydrogen and oxygen - water.

You get: BrO3 + N2H4 -> Br2 + N2 + H2O

# of Br: 1x1 = 1 # of Br: 2x1 = 2
O: 3x1 = 3 O: 1x1 = 1
N: 2x1 = 2 B N: 2x1 = 2
H: 4x1 = 4. H: 2x1 = 2

Br:
Multiply the reactant (left) side by 2 to balance.

O:
You've just multiplied the reactant oxygen by 2 so now the reactant side equals 6. Multiply the product (right) side by six as well.

H:
The product side is now equal to 12. Multiply the reactant side by 3 to balance.

N:
Now you have to balance N because the reactant side has been risen. So multiply the product side by three as well.

You end up with the complete and balanced equation:

2BrO3 + 3N2H4 -> Br2 + 3N2 + 6H2O
4 0
4 years ago
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