Answer:
d
Explanation:
When considering the frequency of the potential alleles of a gene in a population, the total must add up to 1. Think of it like percentages. an allele frequency of 0.3 means 30% of the population carry it (out of a possible 100%).
We know that the frequency of c1 is 0.3. Lets take each option and see if it can be true
a) cannot be less than 0.3. - false. It <em>could </em>be less than 0.3. For example, it could be 0.1, meaning the frequency of allele c3 would be 0.6 (because 0.3 + 0.1 + 0.6 = 1)
b) cannot be greater than 0.3. - false. It <em>could </em>be greater than 0.3. For example, it could be 0.5, meaning the frequency of allele c3 would have to be 0.2 (because 0.3 + 0.5 + 0.2 = 1)
c) is 0.7. - false. It <em>can't </em>be 0.7, because that would mean that the frequency of c3 is 0. (0.7 + 0.3 = 1)
d) cannot be greater than 0.7. - true. It <em>cannot </em>be greater than 0.7, because that would mean that the frequency of c3 is 0. (0.7 + 0.3 = 1)
Answer:
4. B cells become activated by interacting with helper T cells.
1. B cells display antigens in MHC class II receptors on the cell surface.
2. Antibodies released by plasma cells bind to the antigen so they will be destroyed by other cells of the immune system.
3.B cells rearrange their DNA to create a unique B-cell receptor.
5. B cells undergo clonal expansion.
6. B cells digest antigens that bind to the antibodies on their surface.
Explanation:
B-cells get activated by interacting with helper T cells when they bind to the antigen to receptors i.e (MHC class II receptors on the cell surface) on the surface of the cell. Series of activities such as release by plasma cells which cause rearrangement of B cells causes the cell to divide and proliferate. The process through which daughter cells arise from a parent cell called clonal expansion.
Answer:
Diaphoretic may be defined as the medical condition in which the individual has excessive sweating. This might occur due to the internal conditions of the individual and on the external factors as well.
The women is suffering from diarrhea so she must be given fluids that helps in maintaining the electrolyte balance of the body. She require proper medication and health checkup that improves her health condition. She should be given light food that can be easily digestible.
An important role in fungi in an ecosystem is B. Breakind down dead organisms.
Answer:
All EeWw (100%)
Explanation:
This question involves two genes; one coding for earlobes and the other for hairline. According to the question, one parent is homzygous recessive for earlobe but homzygous dominant for hairline i.e. (eeWW) while the other parent is homzygous dominant for earlobe but homzygous recessive for hairline i.e. (EEww).
The cross between the two parents is as follows: eeWW × EEww. The following gamete combination will be produced by each parent:
eeWW - eW, eW, eW, eW
EEww - Ew, Ew, Ew, Ew
Using this gametes in a punnet square, the following proportion of offsprings will likely be produced:
All EeWw
