All categories

3 years ago

Simplify the following expression.

Mathematics

2 answers:

Afina-wow [57]3 years ago

6 0

Answer:

77x+33y

Step-by-step explanation:

Eliminate redundant parentheses

(33x+53y)+(44x−20y)

33+53+44−20

Combine like terms

33x+53y+44x−20y

77+53−20

Combine like terms

77x+53y−20y

77+33

Solution:

77+33

Alenkinab [10]3 years ago

3 0

Answer: The answer would be D.

Step-by-step explanation:

All you have to do is combine like terms.

Pretend that the parenthesis aren't there. 13x + 9y + 38x + 33y.

When you combine like terms, you add or subtract the terms that have the same variable attached.

13x + 38x = 51x.

9y + 33y = 42y

51x + 42y.

I hope I helped.

Brainliest would be appreciated.

You might be interested in

Help i need an answer please dont answer if you are not positive

spayn [35]

What is the area of the shaded region and the circle inside?

$r=20,1m+13,2m=33,3m$
$A_1=\pi r^2$
$A_1=33,3^2\pi$
$A_1=1108,89\pi$

What is the area of the circle inside?

$A_2=20,1^2\pi$
$A_2=404,01\pi$

What is the area of the shaded region?

$1108,89\pi -404,01\pi =704,88\pi$
$704,88\pi \approx 704,88*3,14\approx 2213,3232\approx \underline{2213,32}$

The answer: 2213,32 :)

5 0

3 years ago

Halppppppppppppppppppp

Hatshy [7]

Answer:

Yes

Step-by-step explanation:

$y\leq 3x+9\\\\8\leq 3(7)+9\\\\8\leq 21+9\\\\8\leq 30$

Yes, the given point makes the inequality true. We end up with a true statement.

Hope this helps.

4 0

3 years ago

Suppose you have 18 objects (10 of type A, 5 of type B, and 3 of type C). Objects of type A are indistinguishable from each othe

Paladinen [302]

Answer:

$\binom{18}{5}= 8568$

Step-by-step explanation:

Note that we have in total 18 items. Even though we are given information regarding the amounts of items per type, the general question asks the total number of ways in which you can pick 5 out of the 18 objects, without any restriction on the type of chosen items. Therefore, the information regarding the type is unnecessary to solve the problem.

Recall that given n elements, the different ways of choosing k elements out of n is given by the binomial coefficient $\binom{n}{k})$ .