Question:
A cafeteria offers oranges, apples, or bananas as its fruit option. It offers peas, green beans, or carrots as the vegetable option. Find the number of fruit and vegetable options. If the fruit and the vegetable are chosen at random. what is the probability of getting an orange and carrots? Is it likely or unlikely that a customer would get an orange and carrots?
Answer:
The probability of getting an orange and carrots is 
Step-by-step explanation:
The fruits offered in cafeteria = oranges, apples, or bananas.
The vegetables offered in cafeteria = peas, green beans, or carrots.
There are 3 fruits and 3 vegetables . Therefore the total possible number of outcomes is = 
= 9
Now the probability of getting an orange and carrots =
The possibility is very unlikely to happen
Answer:
Is
Step-by-step explanation:
Correct answer is A I think
Answer:
1. c
2. c
Step-by-step explanation:
1. subract 8 from both sides to get b/-4=-3
multiply both sides by -4 to isolate b
you get b=12
2. combine like terms 3c-4=-8+2c
add 4 to both sides: 3c = -4+2c
subtract 2c from both sides
c=-4
Answer:
The probability that a randomly chosen light bulb will last less than 900 hours is 0.1587.
Step-by-step explanation:
The life span of these light bulbs is normally distributed with a mean of 1000 hours and a standard deviation of 100 hours
Mean = 
Standard deviation =
We are supposed to find the probability that a randomly chosen light bulb will last less than 900 hours.i.e. P(x<900)
So, 
Z=-1
P(x<900)=P(z<-1)=0.1587
Hence the probability that a randomly chosen light bulb will last less than 900 hours is 0.1587.
Answer:
(4 times x) -5
Step-by-step explanation:
Multiply 4 by a number, x, and <em>then</em> subtract 5.
You want to ensure that you're multiplying first before subtracting.
