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2 years ago

14

Can anyone answer these 2?

1 answer:

steposvetlana [31]2 years ago

8 0

Answer:

1.) 12x-10

2.)18x+10

Step-by-step explanation:

You might be interested in

you can buy 3 apples at the quick market for $1.14. you can buy 5 of the same apples at stop and save for $1.10. which place is

PSYCHO15rus [73]

Stop and save you get 2 extra apples and still save $1.10

4 0

2 years ago

Find the x-coordinates where f ' (x)=0 for f(x)=2x+sin(4x) in the interval [0, pi]

MAVERICK [17]

Answer:

The x-coordinate is \dfrac{\pi}{6}[/tex].

Step-by-step explanation:

We are given a function f(x) as:

$f(x)=2x+\sin (4x)$

Now on differentiating both side with respect to x we get that:

$f'(x)=2+4 \cos (4x)$

When $f'(x)=0$

this means that $2+4\cos (4x)=0\\\\4\cos (4x)=-2\\\\\cos(4x)=\dfrac{-1}{2}$

Hence, cosine function takes the negative value in second and third quadrant but we have to only find the value in the interval $[0,\pi]$ .

also we know that $\cos (\dfrac{2\pi}{3})=\dfrac{-1}{2}$ ----(1) (which lie in the second quadrant)

so on comparing our equation with equation (1) we obtain:

$4x=\dfrac{2\pi}{3}\\\\x=\dfrac{\pi}{6}$

Hence, the x-coordinates where $f'(x)=0$ for $f(x)=2x+\sin(4x)$ is $\dfrac{\pi}{6}$ .

5 0

3 years ago

Ronch [10]

Answer:

<em><u>1 and 5</u></em>

Step-by-step explanation:

The squares have a side length of 10 and 1 square side is the radius of the half-circles. Since there are two half-circles, find the circumference for one full circle:

$C=2\pi r$

Insert the radius:

$r=10\\C=2\pi *10$

Simplify pi:

$C=2*3.14*10$

Simplify multiplication:

$C=6.28*10\\C=62.8$

The circumference of the circles is 62.8. Now find the perimeter of the exposed squares with side length 10. There are 4 exposed sides, which equals one square. Find the perimeter:

$P=10+10+10+10\\P=10+10+20\\P=10+30\\P=40$

Add the perimeter of the circle and the square together:

$P=62.8+40=102.8$

Now see which of the options gives you the perimeter:

1. $40+20\pi =102.8$ ****

2. $unavailable$

3. $120+20\pi =182.8$

4. $300+100\pi =614.2$

5. $10+10+10\pi +10+10+10\pi =102.8$ ****

Finito.

7 0

2 years ago

FRANK has a paper clip.it has a mass of 9g and a volume of 3cm3.what is its density?

Pachacha [2.7K]

Answer:

<h2>3 g/cm³</h2>

Step-by-step explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question we have

$density = \frac{9}{3} = 3 \\$

We have the final answer as

<h3>3 g/cm³</h3>

Hope this helps you

7 0

2 years ago

If log2 5 = k, determine an expression for log32 5 in terms of k.

lukranit [14]

Answer:

$log_3_2(5)=\frac{1}{5} k$

Step-by-step explanation:

Let's start by using change of base property:

$log_b(x)=\frac{log_a(x)}{log_a(b)}$

So, for $log_2(5)$

$log_2(5)=k=\frac{log(5)}{log(2)}\hspace{10}(1)$

Now, using change of base for $log_3_2(5)$

$log_3_2(5)=\frac{log(5)}{log(32)}$

You can express $32$ as:

$2^5$

Using reduction of power property:

$log_z(x^y)=ylog_z(x)$

$log(32)=log(2^5)=5log(2)$

Therefore:

$log_3_2(5)=\frac{log(5)}{5*log(2)}=\frac{1}{5} \frac{log(5)}{log(2)}\hspace{10}(2)$

As you can see the only difference between (1) and (2) is the coefficient $\frac{1}{5}$ :

So:

$\frac{log(5)}{log(2)} =k\\$

$log_3_2(5)=\frac{1}{5} \frac{log(5)}{log(2)} =\frac{1}{5} k$

6 0

2 years ago