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2 years ago

Evaluate - 1 - ( - z ) where z = -2

Mathematics

2 answers:

mr_godi [17]2 years ago

6 0

-1+z is the answers

shtirl [24]2 years ago

4 0

Answer:

-3

Step-by-step explanation:

To solve you replace the -z with 2 because the -2=z not -z. With the z in parenthesis being negative it basically means invers so you would put the invers or opposite of -2 in the parentheses.

-1-(2)

-1+-2

=-3

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$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_1 -\hat p_2) \pm z_{\alpha/2} \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2 (1-\hat p_2)}{n_2}}$

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And we know that the margin of erro is given by:

$ME=z_{\alpha/2} \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2 (1-\hat p_2)}{n_2}}$

We have all the values except the value for $z_{\alpha/2}$

So we can find it like this:

$0.1533=z_{\alpha/2} \sqrt{\frac{0.768(1-0.768)}{92} +\frac{0.646 (1-0.646)}{95}}$

And solving for $z_{\alpha/2}$ we got:

$z_{\alpha/2}=2.326$

And we can find the value for $\alpha/2$ with the following excel code:

"=1-NORM.DIST(2.326,0,1,TRUE)"

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