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Harman [31]
2 years ago
7

a rectangle is made by joining two squares adjacent to each other as shown below. if one squared has an area of 144 squared cent

imeters what is the area of the rectangle?​
Mathematics
1 answer:
liberstina [14]2 years ago
3 0

Answer:

Hello! After reading your question I have deduced that the correct answer is 288² cm.

Step-by-step explanation:

The way I came to this conclusion was as follows:

Firstly:

If said rectangle is two squares put side by side (adjacent), then a valid assumption is that both squares are the same size.

This is because all four sides of a square have to be equal.

Thus if the two squares are joined together on one side, then all the other sides of both the squares will be the same length.

Thus both of the squares are going to be the same size, so they will have the same area.

Secondly:

If the area of one square is 144² cm then the area of the other square should also be 144² cm.

Thus if you combine the areas of both the squares, that make up the rectangle, you are left with the area of the rectangle being 288² cm.

I hope this helped!

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3 3/5 + 1 1/6 answer as a fraction
Diano4ka-milaya [45]

Answer:

  • \boxed{\sf{4\dfrac{23}{30} }}

Step-by-step explanation:

It is necessary to add the whole numbers of fractions from left to right in order to solve this problem.

<h3>3 3/5+1 1/6</h3>

<u>First, you have to add the whole numbers.</u>

3+1=4

<u>After that, you can combine by a fraction.</u>

6*3=18

18/5+ 1 1/6

1+6=7

7/6

<u>Rewrite the problem down.</u>

18/5+7/6

<u>Solve.</u>

5*6=30

143/30

=23/30

\boxed{\sf{4\dfrac{23}{30} }}

  • <u>Therefore, the final answer is 4 23/30.</u>
<h3 />

I hope this helps you! Let me know if my answer is wrong or not.

5 0
3 years ago
PLEASE HELP ME ON THIS!!!!
exis [7]
The last two choices are appropriate.

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7 0
4 years ago
The function A(b) relates the area of a trapezoid with a given height of 12 and
Flura [38]

Answer:

B(a)=\frac{a}{6}-9

Step-by-step explanation:

see the attached figure , to better understand the problem

we have

A(b)=12(\frac{b+9}{2})

where

A(b) ---> is the trapezoid's area

b ---> is the other base value

Solve the equation for b

That means ----> isolate the variable b

Divide 12 by 2 right side

A=6(b+9)

Divide by 6 both sides

\frac{A}{6}=b+9

subtract 9 both sides

\frac{A}{6}-9=b

Rewrite

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Convert to function notation

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5 0
3 years ago
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ddd [48]
2x+ y = -4       5x + 3y = -6
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5x + 3(-4-2x) = -6
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sub x=-6 into 2x+y=-4
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4 0
3 years ago
Evaluate this expression.<br> 3-2<br> lao
Andreyy89

Answer:

1

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