Answer:
The solution code is written in Python
d = 1.5 + random.random() * 6
Explanation:
By presuming the Python random module is imported, we can use the <em>random</em> method to generate a random number. <em>random.random()</em> will give us a value in the range [0, 1). The ensure the lower limit is 1.5 instead of 0, we can add 1.5 to random.random()
This expression will give any value in range [1.5, 2.5)
To ensure the upper limit is set to 7.5, we tweak the previous expression to
- 1.5 + random.random() * 6
This expression will always multiply a random number from [0,1) with 6 and then only added with 1.5. This will always produce a random number that fulfill the inequality 1.5 ≤ d < 7.5
Answer:
A trial balance will not balance if both sides do not equal, and the reason has to be explored and corrected.
Explanation:
The debit side and the credit side must balance, meaning the value of the debits should equal the value of the credit
Answer:
Input example:
select the funcion: 1
write the 1sd number2
write the 2nd number1
value is 2.000000
Explanation:
#include <stdio.h>
main()
{
//define the variables as float
float a, b, c, e;
char d;
while (1)
{
//input values
printf("select the function: ");
scanf("%c",&d);
printf("write the 1sd number");
scanf("%f",&a);
getchar();
printf("write the 2nd number");
scanf("%f",&b);
getchar();
if (d=='%')
{
a=a*b/100;
}
if (d=='*')
{
a=a*b;
}
if (d=='+')
{
a=a+b;
}
if (d=='/')
{
a=a/b;
}
if (d=='-')
{
a=a-b;
}
printf("value is %f \n",a);
}
printf("final value is %f",a);
getchar();
}
Step 1: Start
Step 2: Declare variables num1, num2 and sum.
Step 3: Read values for num1, num2.
Step 4: Add num1 and num2 and assign the result to a variable sum.
Step 5: Display sum
Step 6: Stop
#include
int main()
{
int num1,num2,sum;
printf("\n Enter the first number to be added: ");
scanf("%d",&num1);
printf("\n Enter the second number to be added: ");
scanf("%d",&num2);
sum = num1 + num2;
printf("\n The sum of two numbers is: %d",sum);
return 0;
}
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