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3 years ago

How does the distance between the planet and the Sun affect its period?

Physics

2 answers:

Goryan [66]3 years ago

6 0

Answer:

The closer a planet is to the sun, the shorter its period of revolution. The farther away a planet is from the sun, the longer its period of revolution. so it depends on how close and how far it is to have a different time period. so if the if it is close then the period of revolution will be shorter because they need more space to have a longer period. if it is spaced out then it will have a longer period because they do have space.

Explanation:

VMariaS [17]3 years ago

3 0

Answer:

The closer a planet is to the sun, the shorter its period of revolution. The farther away a planet is from the sun, the longer its period of revolution.

Explanation:

i hope that helps, have a great day.

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A pencil is rolled off a table of height 0.92 m. If it has horizontal speed pf 1.4 m/s, how long does it take the pencil to reac

Alenkasestr [34]

The distance an object falls, from rest, in gravity is

   D = (1/2) (G) (T²)

'T' is the number seconds it falls.

In this problem,

   0.92 meter = (1/2) (9.8) (T²)

Divide each side by 4.9 : 0.92 / 4.9 = T²

Take the square root
of each side: √(0.92/4.9) = T

      0.433 sec = T

The horizontal speed doesn't make a bit of difference in
how long it takes to reach the floor. BUT ... if you want to
know how far from the table the pencil lands, you can find
that with the horizontal speed.

The pencil is in the air for 0.433 second.
In that time, it travels
   (0.433s) x (1.4 m/s) = 0.606 meter

from the edge of the table.

3 0

3 years ago

Reaction time is the lapse of time between muscular movement and external stimuli. True or false

riadik2000 [5.3K]

False. reaction time would be lapse of time between external stimuli and muscular movement

3 0

3 years ago

Read 2 more answers

A 1500-W electric heater is plugged into the outlet of a 120-V circuit that has a 20-A circuit breaker. You plug an electric hai

Korolek [52]

Answer:

b) 900 W

Explanation:

The breaker trips when the current is equal to 20 A. The power (P) is the ddp (V) multiplied by the current. So, for the electric heater, the current is:

P = V*i

1500 = 120*i

i = 12.5 A

So, to become in 20 A, it's needed 7.5 A, which must come from the hairdryer. Its power must be:

P = 120*7.5

P = 900 W

8 0

3 years ago

There is a current of 0.83 A through a lightbulb in a 120 V circuit. What is the resistance of this lightbulb?

Lemur [1.5K]

Considering the Ohm's law, the resistance of the lightbulb is 144.58 Ω.

<h3>Definition of current</h3>

The flow of electricity through an object, such as a wire, is known as current (I). Its unit of measure is amps (A). So the current is a measure of the speed at which the charge passes a given reference point in a specified direction.

<h3>Definition of voltage</h3>

The driving force (electrical pressure) behind the flow of a current is known as voltage and is measured in volts (V) (voltage can also be referred to as the potential difference or electromotive force). That is, voltage is a measure of the work required to move a charge from one point to another.

<h3>Definition of resistance</h3>

Resistance (R) is the difficulty that a circuit opposes to the flow of a current and it is measured in ohms (Ω).

Ohm's law establishes the relationship between current, voltage, and resistance in an electrical circuit.

This law establishes that the intensity of the current that passes through a circuit is directly proportional to the voltage of the same and inversely proportional to the resistance that it presents.

Mathematically, Ohm's law is expressed as:

$I=\frac{V}{R}$

Where:

I is the current measured in amps (A).
V the voltage measured in volts (V).
R the resistance that is measured in ohms (Ω).

<h3>Resistance of the lightbulb</h3>

In this case, you know that the voltage between two points in a circuit is 120 V and there is a current of 0.83 A.

Replacing in the Ohm's Law:

$0.83A=\frac{120 V}{R}$

Solving:

0.83 A× R= 120 V

$R=\frac{120 V}{0.83A}$

Finally, the resistance of the lightbulb is 144.58 Ω.

Learn more about Ohm's law:

brainly.com/question/13076023

brainly.com/question/17286882

brainly.com/question/2275770

#SPJ1

3 0

2 years ago

Sometimes a person cannot clearly see objects close up or far away. To correct this type of vision, bifocals are often used. The

Rudik [331]

Answer:

1) P₁ = -2 D, 2) P₂ = 6 D

Explanation:

for this exercise in geometric optics let's use the equation of the constructor

$\frac{1}{f} = \frac{1}{p} + \frac{1}{q}$

where f is the focal length, p and q are the distance to the object and the image, respectively

1) to see a distant object it must be at infinity (p = ∞)

$\frac{1}{f_1} = \frac{1}{q}$

q = f₁

2) for an object located at p = 25 cm

$\frac{1}{f_2} = \frac{1}{25} + \frac{1}{q}$

We can that in the two expressions we have the distance to the image, this is the distance where it can be seen clearly in general for a normal person is q = 50 cm

we substitute in the equations

1) f₁ = -50 cm

$\frac{1}{f_2} = \frac{1}{25} + \frac{1}{50}$

$\frac{1}{f_2}$ = 0.06

f₂ = 16.67 cm

the expression for the power of the lenses is

P = $\frac{1}{f}$

where the focal length is in meters

1) P₁ = 1/0.50

P₁ = -2 D

2) P₂ = 1 /0.16667

P₂ = 6 D

4 0

3 years ago