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uysha [10]
3 years ago
12

What is it called when the moon passes through the penumbra of Earth’s shadow?(1 point)

Physics
1 answer:
skad [1K]3 years ago
8 0

Answer:  I'm not sure, but I think it would be a <em>total lunar eclipse </em>

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An experiment that produces waves on a string is analyzed, and the experimental value for the wave speed is found to be 66 m/s.
Alexandra [31]

4.8 is the correct answer

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On a separate sheet of paper, tell why scientists in different countries can easily compare the amount of matter in similar obje
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A gray kangaroo can bound across level ground with each jump carrying it 9.1 m from the takeoff point. Typically the kangaroo le
Alona [7]

Answer:

u = 10.63 m/s

h = 1.10 m

Explanation:

For Take-off speed ..

by using the standard range equation we have

R = u² sin2θ/g

R = 9.1 m

θ = 26º,

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u² = \frac{Rg}{sin2\theta}

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u^2 = 113.17

u = 10.63 m/s

for Max height

using the standard h(max) equation ..

v^2 = (v_osin\theta)^2 -2gh

h =\frac{(v_o^2sin\theta)^2}{2g}

h  =  \frac{(113.17)(sin26)^2}{(2 x 9.80)}}

h = 1.10 m

7 0
3 years ago
Which has greater kinetic energy, a car traveling at 40 mph or a half-as-massive car traveling at 80 mph?
ziro4ka [17]

Answer:

The 80 mph car

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8 0
2 years ago
A 40 cm wire with a radius of 3 cm is oriented along the y axis and carries a current of 2 A. What is the magnitude of the magne
ZanzabumX [31]

Answer:

a) B = 1.99 x 10⁻⁴ Tesla

b) B = 0.88 x 10⁻⁴ Tesla

Explanation:

According to Biot - Savart Law, the magnetic field due to a currnt carrying straight wire is given as:

B = μ₀ I L/4πr²

where,

μ₀ = permebility of free space = 1.25 x 10⁻⁶ H m⁻¹

I = current = 2 A

L = Length of wire = 40 cm = 0.4 m

a)

r = radius of magnetic field = 2 cm = 0.02 m

Therefore,

B = (1.25 x 10⁻⁶ H m⁻¹)(2 A)(0.4 m)/4π(0.02 m)²

<u>B = 1.99 x 10⁻⁴ Tesla</u>

<u></u>

b)

r = radius of magnetic field = 3 cm = 0.03 m

Therefore,

B = (1.25 x 10⁻⁶ H m⁻¹)(2 A)(0.4 m)/4π(0.03 m)²

<u>B = 0.88 x 10⁻⁴ Tesla</u>

7 0
3 years ago
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