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uysha [10]
3 years ago
12

What is it called when the moon passes through the penumbra of Earth’s shadow?(1 point)

Physics
1 answer:
skad [1K]3 years ago
8 0

Answer:  I'm not sure, but I think it would be a <em>total lunar eclipse </em>

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Suppose you have a pendulum clock which keeps correct time on Earth(acceleration due to gravity = 1.6 m/s2). For ever hour inter
kaheart [24]

The moon clock is A) (9.8/1.6)h compared to 1 hour on Earth

Explanation:

The period of a simple pendulum is given by the equation

T=2\pi \sqrt{\frac{L}{g}}

where

L is the length of the pendulum

g is the acceleration of gravity

In this problem, we want to compare the period of the pendulum on Earth with its period on the Moon. The period of the pendulum on Earth is

T_e=2\pi \sqrt{\frac{L}{g_e}}

where

g_e = 9.8 m/s^2 is the acceleration of gravity on Earth

The period of the pendulum on the Moon is

T_m=2\pi \sqrt{\frac{L}{g_m}}

where

g_m = 1.6 m/s^2 is the acceleration of gravity on the Moon

Calculating the ratio of the period on the Moon to the period on the Earth, we find

\frac{T_m}{T_e}=\frac{g_e}{g_m}=\frac{9.8}{1.6}

Therefore, for every hour interval on Earth, the Moon clock will display a time of

A) (9.8/1.6)h

#LearnwithBrainly

6 0
3 years ago
Which algebraic rule describes the transformation?
Paraphin [41]

Answer:

(y) - (x - 2, y + 5)

Explanation:

7 0
3 years ago
The elements from this section of the periodic table all belong to the same
Lady_Fox [76]

Answer:

The answer is:

B) period

3 0
3 years ago
Samiyah pushes a cart with 20 newtons of force. The cart weighs 10 kilograms. How quickly does the cart accelerate?
love history [14]

Answer:

10 newtons

Explanation: 10 of the 20 cancels out and the other 10 is force.

3 0
3 years ago
Read 2 more answers
The given function represents the position of a particle traveling along a horizontal line. s(t) = 2t3 − 3t2 − 36t + 6 for t ≥ 0
igor_vitrenko [27]

1) The velocity of the particle is given by the derivative of the position. So, if we derive s(t), we get the velocity of the particle as a function of the time:

v(t)=s'(t)=(2t^3-3t^2-36t+6)'=6t^2-6t-36

2) The acceleration of the particle is given by the derivative of the velocity. So, if we derive v(t), we get the acceleration of the particle as a function of the time:

a(t)=v'(t)=(6t^2-6t-36)'=12t-6

8 0
3 years ago
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