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valentinak56 [21]
2 years ago
6

A function f is​ _____ on an open interval I​ if, for any choice of x1 and x2 in​ I, with 1 less than

Mathematics
1 answer:
Zepler [3.9K]2 years ago
3 0

Answer:

If f(x_1)\leq f(x_2) whenever x_1\leq x_2 f is <em>increasing</em> on I.

If f(x_1)\geq f(x_2) whenever x_1\leq x_2 f is <em>decreasing</em> on I.

Step-by-step explanation:

These are definitions for real-valued functions f:I→R. To help you remember the definitions, you can interpret them in the following way:

When you choose any two numbers x_1\leq x_2 on I and compare their image under f, the following can happen.

  • f(x_1)\leq f(x_2). Because x2 is bigger than x1, you can think of f also becoming bigger, that is, f is increasing. The bigger the number x2, the bigger f becomes.
  • f(x_1)\geq f(x_2). The bigger the number x2, the smaller f becomes so f is "going down", that is, f is decreasing.

Note that this must hold for ALL choices of x1, x2. There exist many functions that are neither increasing nor decreasing, but usually some definition applies for continuous functions on a small enough interval I.

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General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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  2. Parenthesis
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Step-by-step explanation:

<u>Step 1: Define</u>

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<u>Step 2: Evaluate</u>

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