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3 years ago

How are the concepts of markup and markdown related to the percent equation?

Mathematics

2 answers:

Nataly_w [17]3 years ago

6 0

9514 1404 393

Explanation:

Markup is the name given to the difference between a cost price and a selling price:

cost price + markup = selling price

Markdown is a name given to the difference between a list price or tag price and the actual selling price.

list price - markdown = selling price

Markup and markdown are <em>actual currency amounts</em>. Often, sellers relate them to the cost price or the list price using percentages. That is, the percentage markup can be figured as ...

percent markup = (markup)/(cost price) × 100%

Similarly, the markdown may be expressed as a percentage of the selling price:

percent markdown = (markdown)/(selling price) × 100%

<em>Additional comments</em>

These representations as percentages are often used because a seller is usually interested in having a specific percentage return on money invested. By making the markup a specific percentage of the cost price, that return can be ensured.

Markdown percentages are often important to a buyer. They look for sales that offer a large percentage discount (markdown), sometimes not paying so much attention to the list price.

otez555 [7]3 years ago

5 0

Answer:

Markup is how much to increase prices and markdown is how much to decrease prices. If we are given a markdown percentage, we multiply the percentage with the original price to find how much of a decrease we are getting, then we subtract this difference from the original price to find the marked down price.

Step-by-step explanation:

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Prove or give a counterexample:

ozzi

Answer:

See proof below.

Step-by-step explanation:

True

For this case we need to use the following theorem "If $v_1, v_2,....v_k$ are eigenvectors of an nxn matrix A and the associated eigenvalues $\lambda_1, \lambda_2,...,\lambda_k$ are distinct, then $v_i's$ are linearly independent". Now we can proof the statement like this:

Proof

Let A a nxn matrix and we can assume that A has n distinct real eingenvalues let's say $\lambda_1, \lambda_2, ....,\lambda_n$

From definition of eigenvector for each one $\lambda_i$ needs to have associated an eigenvector $v_i$ for $1 \leq i \leq n$

And using the theorem from before , the n eigenvectors $v_1,....,v_n$ are linearly independent since the $\lambda_i$ $1\leq i \leq n$ are distinct so then we ensure that A is diagonalizable.

4 0

3 years ago

Nolan surveyed 600 of the students in his school about their favorite color. 15% said their favorite color was blue. How many st

IgorLugansk [536]

Answer:

All we have to find the fraction of students who preferred green and go from there.

Subtracting blue and red out of the all students,

1- (1/8+1/4)

1- 3/8

5/8 is the remaining students, in order to find 3/5 of the remaining students, we multiply by 3/5

5/8(2/5) = 3/8

3/8 preferred green, which was 15 students. In order to get 100% of the whole population (1), we multiply by 8/3:

15(8/3) = 40

40 students were surveyed in total.

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

ABC and XYZ are similar. Find the missing side length.

valina [46]

Answer:

Step-by-step explanation:

The easiest way to solve this is by cross multiplying. We can make an equation to find the answer of this by simply taking a side from each triangle and then the variable and equal side on the other triangle, shown below.

$let \: \: ? = x$