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3 years ago

Can some one tell me how to Divide this very big Question You will be a life savor if you do!!!!!!

Mathematics

1 answer:

PolarNik [594]3 years ago

3 0

Answer:

Sorry if i'm wrong lol but i believe its -x^3+0^3+x+4

Step-by-step explanation:

Divide using polynomial division

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Tom took 10 notecards and arranged them in piles of How many piles did Tom make?

mezya [45]

Answer:

If there in piles of 2 you have 2 piles

Step-by-step explanation:

6 0

3 years ago

Please solve i will give brainiest 100 point question ****** do the whole page please need to pass or i will fail its my final t

dmitriy555 [2]

Answer:

1. Find the difference between the areas.

Area of the small rectangle: $(x+2)(x+7)=x^2+7x+2x+14=x^2+9x+14$

Area of the big rectangle: $(x+9)(x+11)=x^2+11x+9x+99=x^2+20x+99$

The difference is: $11x+85$

$( x^2+20x+99)- (x^2+9x+14)=x^2+20x+99-x^2-9x-14=11x+85$

You can solve this question just by looking at the graph.

a) The height is 4 meters.

$f(d)=h=-2d^2+7d+4$

To find the height of the bleachers, we should consider the moment before the shoot, when the distance is equal to 0.

$f(0)=h=-2(0)^2+7(0)+4$

$h=4$

The height is 4 meters.

b) 9 meters.

For $d=1$

$f(1)=h=-2(1)^2+7(1)+4$

$f(1)=h=-2+7+4$

$h=9$

b) The ball travels 4 meters.

But to calculate it, it is when $h=0$

$0=-2d^2+7d+4$

Using the quadratic formula:

$d=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$d=\frac{-7 \pm \sqrt{7^2-4\left(-2\right)4}}{2\left(-2\right)}$

$d=\frac{-7\pm\sqrt{81}}{-4}$

$d=\frac{-7\pm9}{-4}$

It will give us to solutions, once it is a quadratic equation, but we are talking about a positive distance.

$d=-\frac{1}{2} \text{ or }d=4$

In this question, we have to find the area of the cylinder and the sphere.

From the information given, we have

a = 5mm and d = 5mm, therefore the radius is 2.5 mm.

The volume of a cylinder:

$V=\pi r^2h$

$V=\pi (2.5)^2 \cdot 5$

$V=31.25 \pi$

$V_{c} \approx 98.17 \text{ m}^3$

The volume of the sphere:

$V=\frac{4}{3} \pi r^2$

$V_{s} \approx 65.4 \text{ m}^3$

The volume of the capsule is approximately $163.57 \text{ m}^3$

3 0

3 years ago

Find the area of the shaded region. Round to the nearest tenth.

AURORKA [14]

Answer:

3.5 square cm

Step-by-step explanation:

$Area \: of \: both \: squares \\ = {2}^{2} + {3}^{2} \\ = 4 + 9 \\ = 13 \: {cm}^{2} \\ \\ Area \: of \: both \: right \: \triangle s \\ = \frac{1}{2} \times (2 + 3) \times 2 + \frac{1}{2} \times3 \times 3 \\ = 5 \times 1+ 1.5 \times 3 \\ = 5 + 4.5 \\ = 9.5 \: {cm}^{2} \\ \\ Area \: of \:shaded \: region \\ = Area \: of \: both \: squares\\ - Area \: of \: both \: right \: \triangle s \\ = 13 - 9.5 \\ \purple { \boxed{ \bold{Area \: of \:shaded \: region = 3.5 \: {cm}^{2} }}}$

7 0

3 years ago

Yolanda's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs Yolanda $5.20 per pound, and t

MAXImum [283]

Answer:

78 pounds

Step-by-step explanation:

Let's say Yolanda makes a pounds of Type A coffee and b pounds of Type B coffee. Since the total number of pounds is 130, we can write the equation:

a + b = 130

We know the cost of Type A coffee is $5.20/lb and the cost of Type B coffee is $4.05/lb, so since the total cost is $586.30, we can write:

5.20a + 4.05b = 586.30

We can now solve the system of equations:

a + b = 130

5.20a + 4.05b = 586.30

Manipulate the first equation by subtracting b from both sides:

a + b = 130

a = 130 - b

Substitute 130 - b for a in the second equation:

5.20a + 4.05b = 586.30

5.20 * (130 - b) + 4.05b = 586.30

676 - 5.20b + 4.05b = 586.30

Move the terms with b to one side:

1.15b = 89.70

b = 78

Thus, Yolanda used 78 pounds of Type B coffee.

~ an aesthetics lover

7 0

3 years ago

How does the measure of the pink inscribed angle compare with the measure of the blue intercepted arc? How do you know?

Goryan [66]

Answer:

The pink angle is half the angle subtended by the blue arc.

Step-by-step explanation:

Given

See attachment for circle

Required

Compare the pink angle to the blue arc

Let the pink angle be x and the angle subtended by the blue arc be y.

So, we have:

$x \to$ angle at circumference

$y \to$ angle subtended by arc

The relationship between x and y is:

$y =2x$

Make x the subject

$x = \frac{1}{2}y$

7 0

3 years ago