Answer:
The value of Car B will become greater than the value of car A during the fifth year.
Step-by-step explanation:
Note: See the attached excel file for calculation of beginning and ending values of Cars A and B.
In the attached excel file, the following are used:
Annual Depreciation expense of Car A = Initial value of Car A * Depreciates rate of Car A = 30,000 * 20% = 6,000
Annual Depreciation expense of Car B from Year 1 to Year 6 = Initial value of Car B * Depreciates rate of Car B = 20,000 * 15% = 3,000
Annual Depreciation expense of Car B in Year 7 = Beginning value of Car B in Year 7 = 2,000
Conclusion
Since the 8,000 Beginning value of Car B in Year 5 is greater than the 6,000 Beginning value of Car A in Year 5, it therefore implies that the value Car B becomes greater than the value of car A during the fifth year.
Answer:
8x+8?
Step-by-step explanation:
2x+6x=8x
5+3=8
Find the perimeter of the polygon with the vertices g(2, 4), h(2,−3), j(−2,−3), g(2, 4), h(2,−3), j(−2,−3), and k(−2, 4)k(−2, 4)
Julli [10]
<span>The distance between g and h is sqrt[(2-2)^2+(4+3)^2]=7
The distance between h and j is sqrt[(2+2)^2+(-3+3)^2]=4
The distance between j and k is sqrt[(-2+2)^2+(-3-4)^2]=7
The distance between k and g is sqrt[(-2-2)^2+(4-4)^2]=4
The perimeter of the polygon is 7+4+7+4=22</span>
<span>π<span>r^2</span></span><span>h/<span>3
this is a formula if it is a right angle cone
</span></span>π(4)^2 (9)/3
exponent, 4^2 then times by π
<span>after times by (9/3)=
≈150.8
I think, double check and see if right</span>
<span>-4x + y = -25 y = 4x - 25
-6x - 6y = 0 </span>
-6x - 6(4x - 25) = 0
-6x - 24x + 150 = 0
-30x + 150 = 0
-30x = -150
x = 5
y = 4(5) - 25
y = 20 - 25
y = -5
(5, -5)
