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ella [17]
2 years ago
6

What is 4 1/2 - 1 8/10= in Fractions

Mathematics
2 answers:
ivolga24 [154]2 years ago
7 0

Answer:

4 1/2= 9/2

1 8/10= 18/10= 9/5

9/2-9/5=

(45-18) /10=

27/10 or 2 7/10

Step-by-step explanation:

umka21 [38]2 years ago
3 0

4\frac{1}{2} - 1\frac{8}{10} = \frac{9}{2}- \frac{9}{5} = \frac{27}{10}

ok done. Thank to me :>

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Point S is on line segment RT given ST=3x-8, RT = 4x, and RS = 4x - 7, determine the numerical length of RT
seraphim [82]

Answer:

20

Step-by-step explanation:

Segment ST is half and RS is the other half. RT is the whole line so adding ST and RS will get you RT. 4x-7+3x-8=4x. solve for x which will get you 5. Replace the x with 5 in 4x (for segment RT) will get you an answer of 20 for the whole line.

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Kaley cuts half of a loaf of bread into 4 equal parts. What fraction of the whole loaf does each of the 4 parts represent?
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The answer is 1/4

Step-by-step explanation:

When you split something into fourths, you each get 1/4 of it.

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According to a 2018 survey by Bankrate, 20% of adults in the United States save nothing for retirement (CNBC website). Suppose t
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Answer:

0.5981 = 59.81% probability that three or less of the selected adults have saved nothing for retirement

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they save nothing for retirement, or they save something. The probability of an adult saving nothing for retirement is independent of any other adult. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

20% of adults in the United States save nothing for retirement (CNBC website).

This means that p = 0.2

Suppose that sixteen adults in the United States are selected randomly.

This means that n = 16

What is the probability that three or less of the selected adults have saved nothing for retirement?

This is:

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{16,0}.(0.2)^{0}.(0.8)^{16} = 0.0281

P(X = 1) = C_{16,1}.(0.2)^{1}.(0.8)^{15} = 0.1126

P(X = 2) = C_{16,2}.(0.2)^{2}.(0.8)^{14} = 0.2111

P(X = 3) = C_{16,3}.(0.2)^{3}.(0.8)^{13} = 0.2463

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0281 + 0.1126 + 0.2111 + 0.2463 = 0.5981

0.5981 = 59.81% probability that three or less of the selected adults have saved nothing for retirement

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Step-by-step explanation:

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