Hello I am in a math 95 class. my names drew and I was looking at a problem having to do with exponential equations .

1 answer:

5 0

If it's an exponential model, then we have the original value (1.32 million, or t=0) times something (we can call this y) to the power of another something (we can call it x) equals 2008. Since 2008-2006=2, it may be wise to separate it into 2 year increments. Therefore, if 1.32*(y^x)=1.7, then we can write y as the change every 2 years (in terms of the ratio, or 1.7/1.32 due to that 1.32*1/7/1.32=1.7 since 2 years is the first increment and x is therefore 1) and x as the number of 2 year differences). Since y=1.7/1.32 and 2024-2006=18 (to get it into 2 year increments, we have 18/2=9), we have 1.32*((1.7/1.32)^9)=around <span>12.87 million people</span>

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Construct a 99% confidence interval to estimate the population proportion with a sample proportion equal to 0.36 and a sample s

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Using the z-distribution, the 99% confidence interval to estimate the population proportion is: (0.2364, 0.4836).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

In this problem, we have a 99% confidence level, hence $\alpha = 0.99$ , z is the value of Z that has a p-value of $\frac{1+0.99}{2} = 0.995$ , so the critical value is z = 2.575.