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natka813 [3]
2 years ago
14

When using re-grouping to solve 21 x 43, what are the four products that would be calculated and then added?

Mathematics
2 answers:
Butoxors [25]2 years ago
7 0
The third one because 21 times 43 is 903 and 800 + 40 + 60 + 3 = 903
pshichka [43]2 years ago
3 0

Answer:

c

Step-by-step explanation:

21×43

=(20+1)×(40+3)

=800+40+60+3

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