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natka813 [3]
3 years ago
14

When using re-grouping to solve 21 x 43, what are the four products that would be calculated and then added?

Mathematics
2 answers:
Butoxors [25]3 years ago
7 0
The third one because 21 times 43 is 903 and 800 + 40 + 60 + 3 = 903
pshichka [43]3 years ago
3 0

Answer:

c

Step-by-step explanation:

21×43

=(20+1)×(40+3)

=800+40+60+3

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<em>Now</em><em> </em><em>time</em><em> </em><em>to</em><em> </em><em>solve</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>area</em><em> </em><em>formula</em><em>.</em>

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3 0
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If Julia needs 3 1/4 cups of oatmeal, how many 1/4 cups of oatmeal will she use
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Finally, we see that there is \frac{1}{4} cup of extra oatmeal that Julia wants, so we add one more to our sum.

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