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Lena [83]
3 years ago
5

These are 256 in a box.these are composed of apples,oranges,and ponkans. If their ratio is 3:5:6 respectively.how many apples ar

e their?
Mathematics
1 answer:
nataly862011 [7]3 years ago
4 0

x is some whole number so 3x represents the number of apples, 5x is the number of oranges and 6x is the number of ponkans. The numbers 3x, 5x and 6x are also whole numbers as well. They add up to 256 total pieces of fruit. Solve the equation below for x

3x+5x+6x = 256

14x = 256

14x/14 = 256/14

x = 18.29

since x is not a whole number, there is something wrong with the initial problem. Please double check to make sure there isn't a typo.

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Whats next 2 numbers in this pattern 4,20,100,500.....
Korolek [52]
The next two patterns are 2,500 12,500
7 0
3 years ago
How can we solve this?
Delvig [45]
Both angles will equal 180, as there is a line bisecting line AB to create the two angles.

Set up the following equation to have both angles equal 180:

(x + 35) + (x - 23) = 180

x + 35 + x - 23 = 180

Combine like terms:

x + x = 2x
35 - 23 = 12

2x + 12 = 180

Subtract 12 from both sides:

2x = 168

Divide both sides by 2:

x = 84

We now know the value of x, so plug it into the equation we set up:

(84 + 35) + (84 - 23) = 180

119 + 61 = 180

An obtuse angle will have a measure above 90 degrees. The number on the left side that is above 90 degrees is 119. This would be the measure for the obtuse angle.

The obtuse angle is 119 degrees wide.
8 0
3 years ago
Use the formula r=log10^i where r is the measure of the richter scale i is the intensity, to find the richter scale , measuremen
lara [203]
Hi, thank you for posting your question here at Brainly.

Simply substitute the value of the intensity to the variable i. Taking its logarithm to the base 10, the answer would be 7.8. Hence, 6 million ergs is equivalent to 7.8 based on the Richter scale.
3 0
3 years ago
Read 2 more answers
Evaluate the integral by changing to polar coordinatesye^x dA, where R is in the first quadrant enclosed by the circle x^2+y^2=2
34kurt
\displaystyle\iint_Rye^x\,\mathrm dA=\int_{\theta=0}^{\theta=\pi/2}\int_{r=0}^{r=5}r^2\sin\theta e^{r\cos\theta}\,\mathrm dr\,\mathrm d\theta

which follows from the usual change of coordinates via

\begin{cases}\mathbf x(r,\theta)=r\cos\theta\\\mathbf y(r,\theta)=r\sin\theta\end{cases}

and Jacobian determinant

|\det J|=\left|\begin{vmatrix}\mathbf x_r&\mathbf x_\theta\\\mathbf y_r&\mathbf y_\theta\end{vmatrix}\right|=|r|

Swap the order, so that the integral is

\displaystyle\int_{r=0}^{r=5}\int_{\theta=0}^{\theta=\pi/2}r^2\sin\theta e^{r\cos\theta}\,\mathrm d\theta\,\mathrm dr

and now let \sigma=r\cos\theta, so that \mathrm d\sigma=-r\sin\theta. Now, you have

\displaystyle\int_{r=0}^{r=5}\int_{\sigma=0}^{\sigma=r}re^\sigma\,\mathrm d\sigma\,\mathrm dr=\int_{r=0}^{r=5}r(e^r-1)\,\mathrm dr=4e^5-\dfrac{23}2
7 0
3 years ago
Determine the number of possible solutions for a triangle with B=37 degrees, a=32, b=27
vladimir1956 [14]

Answer:

Two possible solutions

Step-by-step explanation:

we know that

Applying the law of sines

\frac{a}{sin(A)}=\frac{b}{Sin(B)}=\frac{c}{Sin(C)}

we have

a=32\ units

b=27\ units

B=37\°

step 1

Find the measure of angle A

\frac{a}{sin(A)}=\frac{b}{Sin(B)}

substitute the values

\frac{32}{sin(A)}=\frac{27}{Sin(37\°)}

sin(A)=(32)Sin(37\°)/27=0.71326

A=arcsin(0.71326)=45.5\°

The measure of angle A could have two measures

the first measure-------> A=45.5\°

the second measure -----> A=180\°-45.5\°=134.5\°

step 2

Find the first measure of angle C

Remember that the sum of the internal angles of a triangle must be equal to  180\°

A+B+C=180\°

substitute the values

A=45.5\°

B=37\°

45.5\°+37\°+C=180\°

C=180\°-(45.5\°+37\°)=97.5\°

step 3

Find the first length of side c

\frac{a}{sin(A)}=\frac{c}{Sin(C)}

substitute the values

\frac{32}{sin(37\°)}=\frac{c}{Sin(97.5\°)}

c=Sin(97.5\°)\frac{32}{sin(37\°)}=52.7\ units

therefore

the measures for the first solution of the triangle are

A=45.5\° , a=32\ units

B=37\° , b=27\ units

C=97.5\° , b=52.7\ units

step 4    

Find the second measure of angle C with the second measure of angle A

Remember that the sum of the internal angles of a triangle must be equal to  180\°

A+B+C=180\°

substitute the values

A=134.5\°

B=37\°

134.5\°+37\°+C=180\°

C=180\°-(134.5\°+37\°)=8.5\°

step 5

Find the second length of side c

\frac{a}{sin(A)}=\frac{c}{Sin(C)}

substitute the values

\frac{32}{sin(37\°)}=\frac{c}{Sin(8.5\°)}

c=Sin(8.5\°)\frac{32}{sin(37\°)}=7.9\ units

therefore

the measures for the second solution of the triangle are

A=45.5\° , a=32\ units

B=37\° , b=27\ units

C=8.5\° , b=7.9\ units

6 0
3 years ago
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