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Volgvan
2 years ago
9

A band earns $\frac{2}{3}$

Mathematics
1 answer:
ioda2 years ago
3 0

Answer:

brainly.com/question/1913058

Step-by-step explanation:

there hope this helps

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Tan9 - tan27 - tan63 + tan 81 = ?
ludmilkaskok [199]
Tan9−tan27−tan63−tan81
tan9+tan81−tan27−tan63
sin9/cos9+sin81/cos81−sin27/cos27−sin63/cos63
sin90/cos81cos9−sin90/cos63cos27
1/sin9cos9−1/sin27cos27
2/sin18−2/sin54
(2)sin54−sin18/sin18sin54
4cos36sin18/sin18cos36=4
8 0
2 years ago
If the area of a trapezoid is 234 square units what is the value of x
olganol [36]
h=9
A=((a+b)/2)h
234=((32+20)/2)h
234=(52/2)h
234=26h
9=h

6 0
3 years ago
Read 2 more answers
Which number will have the same result when rounded to the nearest ten or hundred A-97 B-118and5 C-179 D-5091
slamgirl [31]
Lets round it to the nearest ten
A 97 ====> 100
B 118 ===> 120
C 179 ===> 180
D 5091 ==> 5090
No result yet, lets round to the nearest hindred.
A 97 ====> 100
B 118 ===> 100
C 179 ===> 180
D 5091 ==> 5100
As we can see only A give the same result when we round it to the nearest hundred and nearest ten.

5 0
3 years ago
The graph of y = |2 is shifted to the left by 6 units.<br> What is the equation of the new graph?
Tasya [4]

Answer:

From your question, I am assuming you are talking about an absolute value graph. In this case the answer would be y = |2 + 6|

Step-by-step explanation: Always remember, when you are graphing absolute value graphs:

When you shift left or right, you put the amount you are shifting inside the absolute value sign.

When you are shifting up or down, you put the amount you are shifting outside the absolute value sign.

When shifting left on a graph, you usually think of subtraction. However, when dealing with absolute value graphs, when you are shifting left, you use addition, as you can see in this problem.

The same goes for right. You use subtraction when shifting right, contrary to what you may think.

However, when you go up, you still use addition, and when you shift down, you still use subtraction.

3 0
3 years ago
The fourth term of an Arithmetic Sequence is equal to 3 times the first term, and the seventh term exceeds twice the third term
11Alexandr11 [23.1K]

Answer:

The first term is 3. The common difference is 2.

Step-by-step explanation:

The first term is x.

The common difference is d.

The second term is x + d.

3rd term: x + 2d

4th term: x + 3d

7th term: x + 6d

"The fourth term of an Arithmetic Sequence is equal to 3 times the first term"

x + 3d = 3 * x       Eq. 1

"the seventh term exceeds twice the third term by 1"

x + 6d = 2(x + 2d) + 1       Eq. 2

Simplify Eq. 1:

2x = 3d

Simplify Eq. 2:

x + 6d = 2x + 4d + 1

x = 2d - 1

Multiply both sides of the last equation by 2.

2x = 4d - 2

2x = 3d   (simplified Eq. 1)

Since 2x = 2x, then the right sides are equal.

3d = 4d - 2

d = 2

2x = 3d

2x = 3(2)

2x = 6

x = 3

Answer: The first term is 3. The common difference is 2.

8 0
3 years ago
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