Answer: Dip the pH paper into each test tube and lay it on the table to let it change color. Use a transfer pipet to remove a few drops from the solution to drop onto the paper. Wait a minute or so before reading color. Use the same piece of indicator paper for each solution to conserve paper.
The best method to solve how many grams of sodium nitrate that will be dissolve in water at 20 degrees Celsius is to use solubility table. Based on the solubility table, 88.3 g will dissolve in water in a 100g NaNO3. Therefore, get the percentage and multiply it to 50g. The answer is 44.15g
Its nitrogen as its outer electron is closer to the nucleus so there will be a stronger electrostatic attraction between it and its nucleus
hope that helps
Answer:
69.7% is percent yield
Explanation:
Based on the reaction:
3Ca(NO3)2(aq) + 2Na3PO4(aq) → Ca3(PO4)2(s) + 6NaNO3(aq)
2 moles of Na3PO4 react producing 6 moles of NaNO3.
As 24.2 moles of Na3PO4 react, theoretical moles of NaNO3 produced are:
24.2 moles Na3PO4 * (6 moles NaNO3 / 2 moles Na3PO4) =
72.6 moles of NaNO3
As there are produced 50.6 moles of NaNO3, percent yield is:
50.6 moles NaNO3 / 72.6 moles NaNO3 =
<h3>69.7% is percent yield</h3>
Answer:
The answer is 200mL each amount have the same mass
Explanation:
100mL +100ML= 200mL mass in each container