Question

What volume will 1.25 liters of carbon dioxide occupy at 50.0ÁC if the pressure changes from 0.865 atm to 0.820 atm?

Answer 1

Temperature = 50°C = constant => PV = constant

1.25 L * 0.865 atm = X*0.820 atm => X = 1.25L*0.865atm/0.820atm = 1.32 L

Answer: 1.32 liters

Answer 2

Answer:

             1.32 L

Solution:

              According to Boyle's Law, " The Volume of a given mass of gas at constant temperature is inversely proportional to the applied Pressure". Mathematically, the initial and final states of gas are given as,

                                     P₁ V₁  =  P₂ V₂    ----------- (1)

Data Given;

                  P₁  =  0.865 atm

                  V₁  =  1.25 L

                  P₂  =  0.820 atm

                  V₂  =  ??

Solving equation 1 for V₂,

                   V₂  =  P₁ V₁ / P₂

Putting values,

                   V₂  =  (0.865 atm × 1.25 L) ÷ 0.820 atm

                   V₂  =  1.318 L ≈ 1.32 L

Result:

          As the Pressure has decreased from 0.865 atm to 0.820 atm, therefore, Volume got increased from 1.25 L to 1.32 L.