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serg [7]
3 years ago
15

102 = V - 66 Addition and subtraction equation practice

Mathematics
2 answers:
Slav-nsk [51]3 years ago
6 0

Answer:

V=168

Step-by-step explanation:

Here,102=V-66

102+66=V

168=V

Sorry If it is wrong.....

satela [25.4K]3 years ago
4 0

<h2><em>⟹</em><em> </em><em>V </em><em>=</em><em> </em><em>1</em><em>6</em><em>8</em></h2>

<h2><em>hope</em><em> it</em><em> helps</em></h2>

<em>see </em><em>the</em><em> attachment</em>

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The stock of Company A gained $0.18 throughout the day and ended at a value of $6.18. By what percentage did the stock rise
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Answer: % increase ≈ 3433%

Step-by-step explanation:

Step 1: work out the difference (increase) between the tow numbers you are comparing.

Increase = New Number - Original Number

Step 2: Divide the increase by the original number and multiply the answer by 100.

% increase = Increase ÷ Original Number x 100

Step 3: Plug in known values

Increase = 6.18

Original Number = 0.18

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5 0
4 years ago
Read 2 more answers
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Y_Kistochka [10]

Answer:

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andreyandreev [35.5K]

Answer:

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8 0
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Step-by-step explanation:

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3 years ago
Approximate the sum of the convergent infinite series the least usingnumber of terms so that the error is less than .0001. What
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Solution :

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Now try, n ≥ 5

$\sum_{n=1 }^{\infty } \frac{(-1)^n}{n ! 2^n}$   = $\sum_{n=1 }^{5 } \frac{(-1)^n}{n ! 2^n}$         (with error 0.0001)

 

$\sum_{n=1 }^{\infty } \frac{(-1)^n}{n ! 2^n}$   = $\frac{-1}{1!2}+\frac{1}{2!2^2}-\frac{1}{3! 2^3}+\frac{1}{4! 2^4}-\frac{1}{5! 2^5}$

$\sum_{n=1 }^{\infty } \frac{(-1)^n}{n ! 2^n}$ = 0.6065104

3 0
3 years ago
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