First notice that the triangle with sides

and the triangle with sides

are similar. This is true because the angle between sides

in the smaller triangle is clearly

, while the angle between sides

in the larger triangle is clearly

. So the triangles are similar with sides

corresponding to

, respectively.
Now both triangles are

, which means there's a convenient ratio between its sides. If the length of the shortest leg is

, then the length of the longer leg is

and the hypotenuse has length

.
Since

is the shortest leg in the larger triangle, it follows that

, so
Answer:

Step-by-step explanation:
The missing parameters are:
--- Cost of marble countertops
--- Cost of retail markup
Required
The cost of marked up price
This implies that we calculate m(c(a))
We have:

can be written as:

Substitute:


Hence, the cost of marked up price is: 
Answer:
-7
Step-by-step explanation:
4-11=-7
She saw 1088 people go down the slide hope my answer helps
Answer
No,100 cm equal 1 m
Step-by-step explanation: