3 years ago Sharman was 2x older, so his age was (c-3)*2
Now his current age is (c-3)*2+3=2c-3
Answer: 220
<u>Step-by-step explanation:</u>
Children (x): $2
Teens (y): $3, 
Adults: (z): $5
Quantity: x + y + z = 570 ⇒ x +
+ z = 570 ⇒ 1.75x + z = 570
Cost: 2x + 3y + 5z = 1950 ⇒ 2x + 3
+ 5z = 1950 ⇒ 2x + 2.25x + 5z = 1950 ⇒ 4.25x + 5z = 1950
Qty: 1.75x + z = 570 → 5(1.75x + z = 570) → 8.75x + 5z = 2850
Cost: 4.25x + 5z = 1950 → -1(4.25x + 5z = 1950 → <u> -4.25x - 5z</u> = <u>-1950 </u>
4.50x = 900
x = 200
Teens (y):
y =
=
= 150
Quantity: x + y + z = 570
200 + 150 + z = 570
350 + z = 570
z = 220
Answer:
You can do it maybe ask you teacher for help! thats always okay!
Step-by-step explanation:
Your answer is
B, two complex roots and two real roots.
By factoring the original equation(which is a difference of two squares), you get:

Because first root is also a difference of two squares, it factors into x - 3 and x +3, your two real roots.
When you factor the second root, the roots are x - 3i and x + 3i.
To prove this, let's multiply them back together:
![[(x-3)(x+3)][(x-3i)(x+3i)]=0\\\\(x^{2}+3x-3x-9)(x^{2}+3xi-3xi-9i^{2})=0\\\\(x^{2}+0x-9)(x^{2}+0xi-9(-1))=0\\\\(x^{2}-9)(x^{2}+9)=0\\\\x^{4}+9x^{2}-9x^{2}-81=0\\\\x^{4}-81=0](https://tex.z-dn.net/?f=%5B%28x-3%29%28x%2B3%29%5D%5B%28x-3i%29%28x%2B3i%29%5D%3D0%5C%5C%5C%5C%28x%5E%7B2%7D%2B3x-3x-9%29%28x%5E%7B2%7D%2B3xi-3xi-9i%5E%7B2%7D%29%3D0%5C%5C%5C%5C%28x%5E%7B2%7D%2B0x-9%29%28x%5E%7B2%7D%2B0xi-9%28-1%29%29%3D0%5C%5C%5C%5C%28x%5E%7B2%7D-9%29%28x%5E%7B2%7D%2B9%29%3D0%5C%5C%5C%5Cx%5E%7B4%7D%2B9x%5E%7B2%7D-9x%5E%7B2%7D-81%3D0%5C%5C%5C%5Cx%5E%7B4%7D-81%3D0)
We reached the equation we started with, so that means that the roots are:
x + 3,
x - 3,
x + 3i, and
x - 3i,
two of which are real and two are complex.
Answer:
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Step-by-step explanation: