Let's say her speed was x miles/hour during the first 3 miles runThen, time = distance/speedt1 = 3/x eq1 In the next 4 miles run, her speed = x-1 miles/hourTime taken:t2 = 4/(x-1) eq2 Now, total time:t1 + t2 = 1 3/5 hourssubstitute t1 and t2 from eqs. 1 and 2 3/x + 4/(x-1) = 1 3/5=> 3/x + 4/(x-1) = 8/5
=> 3(x-1) + 4x = 8x(x-1)/5=> 35x - 15 = 8x2 - 8x=> 8x2 - 43x + 15 = 0=> (8x-3)*(x-5) = 0=> x = 3/8 or 5 miles/hourx can not be 3/8 miles/hour because in that case, the speed during 4 miles run would be 3/8-1 = negative numberi.e. speed during 3 miles segment = 5 miles/hourand speed during 4 miles segment = 5-1 = 4 miles/hour
Answer:
x | y | (x,y)
0 | 35 | (0,35)
3 | 50 | (3,50)
-7 | 0 | (-7,0)
Step-by-step explanation:
Given the equation: 
, to complete the table, plug in the value of x given in the table in each row, to find y.
When x = 0,
(0,35)
When x = 3,
(3,50)
When x = -7,
(-7,0)
Answer:
Since it is vertical angles, 4x - 12 = 88.
Answer is 25
Step-by-step explanation:
88 + 12 = 100
100 / 4 = 25
