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nika2105 [10]
3 years ago
11

What’s the work for 702*59? Multiply with zeros, I’m messing up so I want to see what I’m doing wrong

Mathematics
2 answers:
Illusion [34]3 years ago
8 0

Answer: 41,418


Step-by-step explanation:

702

x 59

_____

6,318

+35,100

_____

41,418

Hope this helps. If you want the paper work I can send it.


Lilit [14]3 years ago
7 0

Answer:

41,418


<u><em>Hope This Helps :-)</em></u>



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Combine 3 and 1/2

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A. csc 20' = csc(90-70)=sec 70

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3×2+4×5=70 prove it's true by adding a bracket​
Rama09 [41]

In the current order of that equation, there is no way to place parentheses/brackets and have it equal 70. I shall explain below.

The factors of 70: 1 and 70, 2 and 35, 5 and 14, 7 and 10

Now, let's experiment with places to put parentheses:

  • 3 x (2 + 4 x 5) = 3(2 + 20) = 3(22) = 66
  • (3 x 2 + 4) x 5 = (6 + 4)(5) = (10)(5) = 50
  • 3 x (2 + 4) x 5 = 3(6)(5) = (18)(5) = 90
  • 3 x 2 + (4 x 5) = 6 + 20 = 26
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  • (3 x 2 + 4 x 5) = (6 + 20) = 26

Notice how the factors of 70 appear nowhere?

The first point is parentheses around the last three constants and it's the closest you'll get. The second point is parentheses around the first three constants and it's up there but not quite 70. The third point is around the middle constants and it's over our number. The fourth, fifth, and sixth points are basically if you were to do the problem straight-up using the order of operations but you added unnecessary parentheses.

The only way this problem <em>would</em> be possible is if you were to switch the places of the 2 and the 4 and make the equation: 3 x 4 + 2 x 5

If it were this, you could do:

(3 x 4 + 2) x 5

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The factors 5 and 14 can be made thus satisfying the equality equation.

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