1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Evgesh-ka [11]
3 years ago
7

I need the answer if you know write with explination if you don't know don't answer ​

Mathematics
1 answer:
yarga [219]3 years ago
8 0

Answer:

ABD ≅ ACD and PQS ≅ PRS

Step-by-step explanation:

For ABD ≅ ACD;

AB = AC = 3.5

BD = CD = 2.5

AD ≅ AD by reflexive

Since all 3 sides are congruent, SSS can be used

For PQS ≅ PRS

PQ≅PR by given

QS≅RS by given

PS≅PS by reflexive property

Since all 3 sides are congruent, SSS can be used and they are congruent

You might be interested in
Find the distance between the point (2, 3) and the line 4x + 3y = 10 (round your answer to the nearest tenth).
Monica [59]

Explanation

Let's first graph the elements:

Using the distance formula we get:

d=\frac{|4(2)+3(3)-10|}{\sqrt{4^2+3^2}}d=\frac{|7|}{\sqrt{25}}=\frac{7}{5}=1.4

4 0
1 year ago
Find the sum of the first 90 terms of the sequence -4,-1,2,5,8
telo118 [61]

Answer:

1655

Step-by-step explanation:

Note the common difference d between consecutive terms of the sequence

d = - 1 - (- 4) = 2 - (- 1) = 5 - 2 = 8 - 5 = 3

This indicates the sequence is arithmetic with sum to n terms

S_{n} = \frac{n}{2} [ 2a₁ + (n - 1)d ]

Here a₁ = - 4, d = 3 and n = 90, thus

S_{90} = \frac{90}{2} [ (2 × - 4) + (89 × 3) ] = 45(- 8 + 267) = 45 × 259 = 1655

4 0
3 years ago
I need to transpose the following equation to find the term (g)<br><br> V^2=2gh
nataly862011 [7]
v^2=2gh\\\\2gh=v^2\ \ \ \ |divide\ both\ sides\ by\ 2h\\\\\boxed{g=\frac{v^2}{2h}}
7 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=1%20%5Cdiv%20%20%28x%20-%202%29%20%28x%20-%203%29%20%2B%201%20%20%5Cdiv%20%28x%20-%202%29%28x%
Anika [276]
I don’t know if you need to show work but here is the answer 2(x-2)/x-3
7 0
3 years ago
manufacturing company produces digital cameras and claim that their products maybe 3% defective. A video company, when purchasin
alexdok [17]

Answer:

P(X>17) = 0.979

Step-by-step explanation:

Probability that a camera is defective, p = 3% = 3/100 = 0.03

20 cameras were randomly selected.i.e sample size, n = 20

Probability that a camera is working, q = 1 - p = 1 - 0.03 = 0.97

Probability that more than 17 cameras are working P ( X > 17)

This is a binomial distribution P(X = r) nCr q^{r} p^{n-r}

nCr = \frac{n!}{(n-r)!r!}

P(X>17) = P(X=18) + P(X=19) + P(X=20)

P(X=18) = 20C18 * 0.97^{18} * 0.03^{20-18}

P(X=18) = 20C18 * 0.97^{18} * 0.03^{2}

P(X=18) = 0.0988

P(X=19) = 20C19 * 0.97^{19} * 0.03^{20-19}

P(X=19) = 20C19 * 0.97^{19} * 0.03^{1}

P(X=19) = 0.3364

P(X=20) = 20C20 * 0.97^{20} * 0.03^{20-20}

P(X=20) = 20C20 * 0.97^{20} * 0.03^{0}

P(X=20) = 0.5438

P(X>17) = 0.0988 + 0.3364 + 0.5438

P(X>17) = 0.979

The probability that there are more than 17 working cameras should be 0.979 for the company to accept the whole batch

6 0
3 years ago
Other questions:
  • I need help on number 11 and 18 on front of The page please Mean Median Mode and range please Thank you
    12·1 answer
  • 72<br> as a product of prime factors.
    14·1 answer
  • If you start with a number, add 2/5, then multiply by 7, the result is 6 3/10. What was the original number?
    12·1 answer
  • At a school for performance art students
    7·1 answer
  • The expanded form of 3(4a) is:
    14·1 answer
  • Can someone help and explain
    8·1 answer
  • A teacher surveyed her class after they had taken a vocabulary test. Eighteen of the students claimed they had studied at least
    10·2 answers
  • Evaluate the function for the given value.
    12·1 answer
  • Can someone explain this to me
    12·1 answer
  • Zack has 18 socks in his drawer. 6 are blue, 6 are red, and 6 are green. How many socks will he need to pull out to be sure he g
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!