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3 years ago

IDENTIFY A PAIR OF SEGMENTS THAT ARE MARKED PERPENDICULAR TO EACH OTHER.

Mathematics

1 answer:

scoray [572]3 years ago

4 0

Answer:

AB is perpendicular to IB

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A building casts a shadow 48feet long. At the same time,a 40 foot tall flagpole casts a shadow 9.6 feet long. What is the height

max2010maxim [7]

Let the height of the shadow be x.
Ratio of length of shadow to height: 48/x = 9.6/40
x = (48 x 40)/9.6 = 200 feet.

8 0

4 years ago

What is the answer to this fraction 4/8+2/8+4/8

Allisa [31]

Answer:

1 2/8 OR 1 1/4

Step-by-step explanation:

4/8 + 2/8 + 4/8 =

6/8 + 4/8 =

10/8 =

1 2/8 OR 1 1/4

<em>Hope that helps!</em>

5 0

4 years ago

Read 2 more answers

Help plz (problly easy for you)

PolarNik [594]

The second option: 4x² - x + 1

All you have to do is add the like terms:

3x² + x² = 4x²

4x - 5x = -x

-2 + 3 = 1

Combine all the results and you will get your solution!

6 0

4 years ago

Find the length between each pair of points (-1, 6) (7, 2)

Alexeev081 [22]

Answer:

$\sqrt{80}$ or $4\sqrt{5}$

Step-by-step explanation:

Using the distance formula:

$d=\sqrt{(7-(-1))^2+(6-2)^2}=\sqrt{8^2+4^2}=\sqrt{64+16}=\sqrt{80}=4\sqrt{5}$

Hope this helps!

8 0

3 years ago

At a store, markers are sold in packages of 12 and pens are sold in packages of 8. What is the least amount of markers and pens

liubo4ka [24]

Given:

Markers are sold in packages of 12 and pens are sold in packages of 8.

To find:

Least amount of markers and pens Rick needs to buy to have an equal number of markers and pens

Solution:

To find the least amount of markers and pens, we need to find the LCM of 12 and 8.

Prime factors of 8 and 12 are

$8=2\times 2\times 2$

$12=2\times 2\times 3$

To find the LCM, multiply all factors but the common factors are included only once.

$LCM(8,12)=2\times 2\times 2\times 3$

$LCM(8,12)=24$

Therefore, the least amount of markers and pens Rick needs to buy to have an equal number of markers and pens is 24.

5 0

4 years ago