IDENTIFY A PAIR OF SEGMENTS THAT ARE MARKED PERPENDICULAR TO EACH OTHER.

mars1129 [50]

29 ...................................................................................................

5 0

4 years ago

In a triangle, the measure of the first angle is twice the measure of the second angle. the measure of the third angle is 96 deg

slavikrds [6]

Lets x = measure of the second angle, so m<2 = x
m<1 = 2x (<span>the measure of the first angle is twice the measure of the second angle)
</span>m<3 = x + 96 (<span>96 degrees more than the measure of the second angle)
</span>
x + 2x + x+ 96 = 180
4x + 96 = 180
4x = 84
x = 21

2x = 2(21) = 42
x + 96 = 21+96 = 117

answer
m<1 = 42
m<2 = 21
m<3 = 117

Double check
sum = 180

m<1 + m<2 +m<3 = 180
42+21+117=180
180=180

4 0

4 years ago

A questionnaire has determined that 20% of the residents of Flaugamuck County own an iPod. Furthermore, 80% of these iPod owners

nydimaria [60]

Answer:

P = 7.14%

The percentage of those 30 years or older that own an ipod is 7.14%

Step-by-step explanation:

Given;

Percentage of ipod owners Pi = 20%

Percentage who don't own ipod Pd = 100-20 = 80%

For age 30 or older;

Percentage of ipod owners who belong to this group

Po = 20% of Pi

Percentage who don't have an ipod but belong to this group Pu = 100-35% = 65% of Pd

The percentage of those 30 years or older that own an ipod is;

P = Po/(Po+Pu) × 100%

Po = 20% of Pi = 20% of 20% = 0.2×20 =4%

Pu = 65% of Pd = 65% of 80% = 0.65×80% = 52%

Substituting the values;

P = 4/(4+52) × 100%

P = 7.14%

5 0

3 years ago

Suppose the object moving is Dave, who hasamassofmo =66kgatrest. Whatis Daveâs mass at 90% of the speed of light? At 99% of the

nignag [31]

Step-by-step explanation:

Formula that relates the mass of an object at rest and its mass when it is moving at a speed v:

$m=\frac{m_o}{\sqrt{1-\frac{v^2}{c^2}}}$

Where :

m = mass of the oebjct in motion

$m_o$ = mass of the object when at rest

v = velocity of a moving object

c = speed of the light = $3\times 0^8 m/s$

We have :

1) Mass of the Dave = $m_o=66 kg$

Velocity of Dave ,v= 90% of speed of light = 0.90c

Mass of the Dave when moving at 90% of the speed of light:

$m=\frac{66 kg}{\sqrt{1-\frac{(0.90c)^2}{c^2}}}$

m = 151.41 kg

Mass of Dave when when moving at 90% of the speed of light is 151.41 kg.

2) Velocity of Dave ,v= 99% of speed of light = 0.99c

Mass of the Dave when moving at 99% of the speed of light:

$m=\frac{66 kg}{\sqrt{1-\frac{(0.99c)^2}{c^2}}}$

m = 467.86 kg

Mass of Dave when when moving at 99% of the speed of light is 467.86 kg.

3) Velocity of Dave ,v= 99.9% of speed of light = 0.999c

Mass of the Dave when moving at 99.9% of the speed of light:

$m=\frac{66 kg}{\sqrt{1-\frac{(0.999c)^2}{c^2}}}$

m = 1,467.17 kg

Mass of Dave when when moving at 99.9% of the speed of light is 1,467.17 kg.

4) Mass of the Dave = $m_o=66 kg$

Velocity of Dave,v=?

Mass of the Dave when moving at v speed of light: 500

$500 kg=\frac{66 kg}{\sqrt{1-\frac{(v)^2}{(3\times 10^8 m/s)^2}}}$

$v=2.973\times 10^8 m/s$

Dave should be moving at speed of $2.973\times 10^8 m/s$ .

4 0

3 years ago

A basketball is shaped like a sphere as shown in the diagram. The basketball has a radius of 4.7 inches.

netineya [11]

Answer:

V≈434.89

Step-by-step explanation:

V=4/3πr^3

plug the numbers in and you get 434.89

8 0

3 years ago