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kap26 [50]
3 years ago
10

Solve each equation 2n-5=21

Mathematics
1 answer:
aleksklad [387]3 years ago
4 0
2n-5=21
add 5 to both sides
2n=26
divide both sides by 2
n=13

I hope I helped! :)
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100 points <br> 1942 divded by 2^4
NARA [144]

Answer: 121.375

Step-by-step explanation:

2^4=16

\frac{1942}{2^4}

\frac{1942}{16}=121.375

5 0
2 years ago
Keith buys 45 tickets for rides at the amusement park. Each ride requires 6 tickets to ride. If Keith already has gone on x ride
Lynna [10]
A is the correct answer if I did it right
3 0
3 years ago
Write 98 as the product of prime factors in ascending order
Dimas [21]

                98

       2           49

               7            7

 so the answer is 2 x 7 x 7, which is 2 x 7^2

7 0
3 years ago
Gavin's dog had a litter of puppies. All of the puppies in this litter were either yellow or black. If there was one less black
mezya [45]

Answer:

Total number of puppies in the litter = 11

Step-by-step explanation:

Let the number of yellow puppies in the litter = y

And the number of black puppies in the litter = b

If there was one less black puppy, ratio of yellow to black puppies = \frac{2}{3}

\frac{y}{b-1}=\frac{2}{3}

2(b - 1) = 3y

3y - 2b = -2 -----(1)

If there was one more black puppy, ratio of yellow puppies to black puppies = \frac{1}{2}

\frac{y}{b+1}=\frac{1}{2}

2y = b + 1

2y - b = 1 -------(2)

Equation (1) - 2× equation (2)

(3y - 2b) - 2(2y - b) = -2 - 2

3y - 4y - 2b + 2b = -4

y = 4

From equation (1),

3×4 - 2b = -2

12 - 2b = -2

-2b = -14

b = 7

Total number of puppies in the litter = 7 + 4 = 11

4 0
3 years ago
Julissa is running a 10-kilometer race at a constant pace. After running for 18 minutes, she completes 2 kilometers. After runni
vodomira [7]
First, we need her speed as it will serve as the slope of the equation.
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time = 18 min
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k = (1/9)t
Where k is the distance in km and t is the time in minutes.
6 0
3 years ago
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