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3 years ago

Solve pls brainliest

Mathematics

2 answers:

LenaWriter [7]3 years ago

7 0

Answer:0.16 bar ontop of 6

Step-by-step explanation:

jekas [21]3 years ago

4 0

Answer:

0.166

Step-by-step explanation:

I did this about 2 years ago

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Help a fellow out please

Liula [17]

Answer:

24.27 cm

Step-by-step explanation:

sin 65 degrees = 22/x, so:

1 x

------------------ = ------

sin 65 deg 22

so x = 22 / (sin 65 deg) = 22/0.906 = 24.27 cm

8 0

3 years ago

Find the surface area of<br> the prism.

tatyana61 [14]

Answer:

Whats the question?

Step-by-step explanation:

6 0

3 years ago

What is 0.7 divided by 2

masha68 [24]

0.7 divided by 2 = 0.35

The answer is 0.35.

4 0

3 years ago

Read 2 more answers

A chain lying on the ground is 10 m long and its mass is 70 kg. How much work (in J) is required to raise one end of the chain t

DerKrebs [107]

Answer:

$W= 34.3 \frac{kg}{s^2} (4^2-0^2)m^2 =548.8 \frac{kg m^2}{s^2} =548.8 J$

Step-by-step explanation:

Data Given: m = 70 kg , g = 9.8 ms^-2, h =10m.

For this case we can use the following formula:

$W = \int_{x_i}^{x_f} F(x) dx$

For this case we need to find an expression for the force in terms of the distance. And since on this case the total distance is 10 m long we can write the expression like this:

$F(x) = \frac{ma}{10m}= \frac{mg}{10m} x$

The only acceleration on this case is the gravity and if we replace the values given we got:

$\frac{70 kg *9.8 m/s^2}{10m} x=68.6 x\frac{kg}{s^2}$

Now we can find the required work with the following integral:

$W= 68.6 \frac{kg}{s^2} \int_{0}^4 x dx$

$W= 34.3 \frac{kg}{s^2} x^2 \Big|_0^4$

$W= 34.3 \frac{kg}{s^2} (4^2-0^2)m^2 =548.8 \frac{kg m^2}{s^2} =548.8 J$

7 0

4 years ago

I i i i i i i i i i i

Lesechka [4]

Answer:

She didn't wasn't supposed to subtract 57, she was suppose to add.

5 0

3 years ago