Answer:
need more info
Step-by-step explanation:
Answer:
13 ft/s
Step-by-step explanation:
t seconds after the boy passes under the balloon the distance between them is ...
d = √((15t)² +(45+5t)²) = √(250t² +450t +2025)
The rate of change of d with respect to t is ...
dd/dt = (500t +450)/(2√(250t² +450t +2025)) = (50t +45)/√(10t² +18t +81)
At t=3, this derivative evaluates to ...
dd/dt = (50·3 +45)/√(90+54+81) = 195/15 = 13
The distance between the boy and the balloon is increasing at the rate of 13 ft per second.
_____
The boy is moving horizontally at 15 ft/s, so his position relative to the spot under the balloon is 15t feet after t seconds.
The balloon starts at 45 feet above the boy and is moving upward at 5 ft/s, so its vertical distance from the spot under the balloon is 45+5t feet after t seconds.
The straight-line distance between the boy and the balloon is found as the hypotenuse of a right triangle with legs 15t and (45+5t). Using the Pythagorean theorem, that distance is ...
d = √((15t)² + (45+5t)²)
Step 1 : Simplify both sides
-5(6a+21)=-15
(-5)(6a)+(-5)(21)=-15
-30a-105=-15
Step 2 : Add 105 to both sides
-30a-105+105=-15+105
-30a=90
Step 3 : Divide both sides by -30
-30a=90
—————
-30 -30
a = -3
Answer:
Step-by-step explanation:
You need to be specific. Did the weight decrease by 60 tons or 60 pounds? I assume tons, but in math, you can't assume.
This problem seems overly simple, so I am wondering if some information is missing. With the given information and assuming the decrease was in fact 60 tons, you would have:
125,890 - 60 = 125,830 tons
<em>8gh x 2g2 x 3h</em>
<em>Simplified is 8 · 3 gghhxx ·2 · 2 </em>
<em>and can also be:</em>
<em>8ghx · 2g · 2x · 3h </em>
<em>24g ₁ ₊ ₁ h ₁ ₊ ₁ x ₁ ₊ ₁ · 2 ₁ ₊ ₁</em>
