Write 5% as a decimal.

1 answer:

3 0

You cannot do it that way. Make sure the question you wrote is correct, because you would divide 5 by 100, not 100 by 5. A simple way is to move the decimal point two points to the left. 5% as a decimal is 0.05.

The answer is false if the question is written this way.

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HI decomposes into its elements according to second-order kinetics. What concentration of HI remains from an initial concentrati

Novosadov [1.4K]

Answer:

Therefore (2.30-0.03747)= 2.2625 M of HI remains from an initial concentration of 2.30 M after 4.5 hours.

Step-by-step explanation:

second order reaction: The rate of reaction proportional to the square of the concentration of reactant.

For second order reaction

$k=\frac{x}{ta(a-x)}$

K is rate constant = 1.6×10⁻³M⁻¹hr⁻¹

a = initial concentration of reactant = 2.30 M

a-x = concentration of reactant after t h

t = time = 4.5 h

Putting the values in the above equation,

$1.6\times 10^{-3}= \frac{x}{4.5 \times 2.30 \times (2.30-x)}$

$\Rightarrow 16.56 \times 10^{-3}\times (2.30-x)= x$

$\Rightarrow 16.56 \times 10^{-3}\times 2.30-16.56 \times 10^{-3}\times x= x$

$\Rightarrow (1+16.56 \times 10^{-3}) x=16.56 \times 10^{-3}\times 2.30$

$\Rightarrow x = 0.03747$

Therefore (2.30-0.03747)= 2.2625 M of HI remains from an initial concentration of 2.30 M after 4.5 hours.

4 0

4 years ago

tom had a platter of chocolate wafers. he ate 5 of them and then gave his brother 3 he then moved on to his baseball team of 8 m

Aloiza [94]

Tom started with total 72 chocolate wafers.

Explanation

The number of chocolate wafers taken by 8 members of the baseball team are in the sequence : $1, 3,5,7,9,11,13,15$

The above sequence is arithmetic sequence with first term(a₁)= 1 and common difference (d) = 2

Formula for Sum of first $n$ terms in arithmetic sequence is....

$S_{n}= \frac{n}{2}[2a_{1}+(n-1)d]$

So, the Sum of 8 terms in that sequence....

$S_{8}= \frac{8}{2}[2(1)+(8-1)(2)]\\ \\ S_{8}= 4[2+7(2)]\\ \\ S_{8}=4(2+14)\\ \\ S_{8}=4(16)=64$

That means, the total number of chocolate wafers taken by the baseball team members is 64. Tom ate 5 and then gave his brother 3 chocolate wafers at first.

So, the total number of chocolate wafers at starting $=64+5+3=72$