All categories

3 years ago

If a hypothesis is rejected at the 5% level of significance, it will always be rejected at the 1% level. Select one: True False

Mathematics

1 answer:

Hunter-Best [27]3 years ago

7 0

Answer:

a. will also not be rejected at the 1% level.

Step-by-step explanation:

A hypothesis is rejected if:

The p-value is larger than the significance level.

Hypothesis is not rejected at a 5% level of significance

This means that the p-value is > 0.05.

At the 1% level:

p-value > 0.01, so it will never be rejected, and thus, the correct answer is given by option a.

Step-by-step explanation:

So yes, True.

You might be interested in

Madelyn just graduated from college and owes $15,100 on her student loans. The bank charges a monthly interest rate of 0.2%. If

Dimas [21]

Answer:

$121

Step-by-step explanation:

A suitable calculator or spreadsheet can tell you the payment amount for the given loan values. The annual interest rate will be 12 times the monthly, rate, or 2.4%. The number of monthly payments in 12 years is 12×12 = 144.

A calculator shows the monthly payment will be about $121.

If you want to figure this "by hand," the amortization formula is used.

A = Pr/(1 -(1+r)^-t)

where P is the loan amount, r is the monthly interest rate, and t is the number of months.

A = 15100(0.002)/(1 -(1.002^-144)) ≈ 120.789 ≈ 121

The monthly payment would be $121.

7 0

2 years ago

The rate of change of the downward velocity of a falling object is the acceleration of gravity (10 meters/sec 2) minus the accel

Alexus [3.1K]

Answer:

See below

Step-by-step explanation:

Write the initial value problem and the solution for the downward velocity for an object that is dropped (not thrown) from a great height.

if v(t) is the speed at time t after being dropped, v'(t) is the acceleration at time t, so the the initial value problem for the downward velocity is

v'(t) = 10 - 0.1v(t)

v(0) = 0 (since the object is dropped)

The equation v'(t)+0.1v(t)=10 is an ordinary first order differential equation with an integrating factor

$\bf e^{\int {0.1dt}}=e^{0.1t}$

so its general solution is

$\bf v(t)=Ce^{-0.1t}+100$

To find C, we use the initial value v(0)=0, so C=-100

and the solution of the initial value problem is

$\bf \boxed{v(t)=-100e^{-0.1t}+100}$

what is the terminal velocity?

The terminal velocity is

$\bf \lim_{t \to\infty}(-100e^{-0.1t}+100)=100\;mt/sec$

How long before the object reaches 90% of terminal velocity?

90% of terminal velocity = 90 m/sec

we look for a t such that

$\bf -100e^{-0.1t}+100=90\rightarrow -100e^{-0.1t}=-10\rightarrow e^{-0.1t}=0.1\\-0.1t=ln(0.1)\rightarrow t=\frac{ln(0.1)}{-0.1}=23.026\;sec$

How far has it fallen by that time?

The distance traveled after t seconds is given by

$\bf \int_{0}^{t}v(t)dt$

So, the distance traveled after 23.026 seconds is

$\bf \int_{0}^{23.026}(-100e^{-0.1t}+100)dt=-100\int_{0}^{23.026}e^{-0.1t}dt+100\int_{0}^{23.026}dt=\\-100(-e^{-0.1*23.026}/0.1+1/0.1)+100*23.026=1,402.6\;mt$

3 0

3 years ago

In the United States, 36 percent of the people have a blood type that is A positive. From a random sample of 150 people from Nor

djverab [1.8K]

Answer:

The standard deviation used in the test statistic is 0.04.

Step-by-step explanation:

A single proportion z-test can be used to determine whether the proportion of people in Norway with a blood type of A positive is different from that in the United States.

The proportion of people in Norway with a blood type of A positive is 36% or 0.36.

The hypothesis can be defined as:

H₀: The proportion of people in Norway with a blood type of A positive is 36%, i.e. p = 0.36.

Hₐ: The proportion of people in Norway with a blood type of A positive is different from 36%, i.e. p ≠ 0.36.

The test statistic is:

$z=\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}}}$