The formula for a triangular pyramid is 1/3AH. A is the area of the base. H is the height of the pyramid. So to find the area of a right triangle, you would use the formula (a x b)/2. So (10 x18)/2 is 90 inches^2. Now you can fill in the first formula. 1/3(90 x 14), which equals 420 inches^3. I hope you find this helpful (if correct.)
Answer:
d
Step-by-step explanation:
x4+28+584+-4847-+6384
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Let KLMN be a trapezoid (see added picture). From the point M put down the trapezoid height MP, then quadrilateral KLMP is square and KP=MP=10.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
Area of KLMN is egual to

sq. units.
Answer:
d) 7(30 + 9) = 7(30) + 7(9)
Step-by-step explanation:
<u>Distributive method</u>:
<u>Here given</u>:
Among the option's:
<u>1st option</u> (7 + 3) (7 + 9) is wrong, changes <u>final answer</u>.
<u>2nd option</u> (7 × 30) + 9 is wrong, changes <u>final answer</u>.
3rd option 39 × 7 shows commutative property of multiplication.
<u>4th option</u> show distributive method.