5' per side or whatever units it's measured in, because 4x5=20
The previous answer from another person got deleted, so I'm here to put it back in my own words.
(Edit: The answer is A)
First of all, you can take 4 out of each, so simplify everything by 4.
4(x^4 - 6x^3 + 9x^2)
Next, you can see that you're able to take out x^2
4x^2(x^2 - 6x + 9)
You can see that both x^2 and 9 are perfect squares, meaning you can crunch them together like this
(x+3)^2 or (x-3)^2
Of course, only one would work, and as fate has it, (x-3)^ produces x^2 - 6x + 9
This would turn the now factored equation into :
4x^2(x-3)^2 or 4x^2(x-3)(x-3), this means the answer is A
Answer: 62
Step-by-Step Explanation:
First Term (a) = 7
Common Difference (d) = 12 - 7 = 5
Term to Find (n) = 12th
Therefore, finding the 12th Term :-
=> a+(n-1)d
= 7 + (12 - 1)5
= 7 + (11)5
= 7 + 55
=> 62
Hence, 12th Term of this AP is 62
Answer:
Solution: x = 2, y = -1 or (2, -1)
Step-by-step explanation:
Equation 1: 2x + y = 3
Equation 2: 5x - 2y = 12
Using the substitution method:
Transform the Equation 1 into its slope-intercept form:
2x + y = 3
2x - 2x + y = -2x + 3
y = 2x + 3
Substitute the value of y = -2x + 3 into Equation 2:
5x - 2y = 12
5x - 2(-2x + 3) = 12
5x + 4x - 6 = 12
9x - 6 = 12
9x - 6 + 6 = 12 + 6
9x = 18
9x/9 = 18/9
x = 2
Substitute the value of x = 2 into Equation 2 to solve for y:
5x - 2y = 12
5(2) - 2y = 12
10 - 2y = 12
10 - 10 - 2y = 12 - 10
-2y = 2
-2y/-2 = 2/-2
y = -1
Double-check whether the values for x and y will provide a true statement for both equations:
Equation 1: 2x + y = 3
2(2) + (-1) = 3
4 - 1 = 3
3 = 3 (True statement)
Equation 2: 5x - 2y = 12
5(2) - 2(-1) = 12
10 + 2 = 12
12 = 12 (True statement)
Therefore, the correct answers are: x = 2; y = -1 or (2, -1).
