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salantis [7]
3 years ago
13

A line passes through the given points. write an equation for the line in point-slope form. then rewrite the equation in slope i

ntercept form.
#1 (-2, 6) (5, 1)
#2 (3, -8) (-2, 5)
#3 (1, 1/2) (3, 2)
Mathematics
1 answer:
rodikova [14]3 years ago
7 0

#1 first we need to solve for slope which is y2-y1/x2-x1

plug in the coordinates and get 1-6/5-(-2) which makes our slope -5/7

then use the equation for point slope form which is:

y-y1=m(x-x1)

then plug in one of the coordinates, I'll use (-2,6), now we have

y-6=-5/7(x+2)

now to make this slope intercept, we just have to solve

y-6=-5/7x-10/7

y=-5/7x+4 4/7

repeat all these steps for 2 and 3

#2: slope = -13/5

plug it in to point slope and get: y+8=-13/5(x-3)

slope intercept:

y+8= -13/5x + 39/5

y= -13/5x -1/5

#3: slope = 3/4

point slope form: y-2=3/4(x-3)

slope intercept: y-2=3/4x-9/4 --> y=3/4x-1/4

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The domain of the relation is 7,13 and the range of the relation is 4,20. I hope this helps.
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