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salantis [7]
3 years ago
13

A line passes through the given points. write an equation for the line in point-slope form. then rewrite the equation in slope i

ntercept form.
#1 (-2, 6) (5, 1)
#2 (3, -8) (-2, 5)
#3 (1, 1/2) (3, 2)
Mathematics
1 answer:
rodikova [14]3 years ago
7 0

#1 first we need to solve for slope which is y2-y1/x2-x1

plug in the coordinates and get 1-6/5-(-2) which makes our slope -5/7

then use the equation for point slope form which is:

y-y1=m(x-x1)

then plug in one of the coordinates, I'll use (-2,6), now we have

y-6=-5/7(x+2)

now to make this slope intercept, we just have to solve

y-6=-5/7x-10/7

y=-5/7x+4 4/7

repeat all these steps for 2 and 3

#2: slope = -13/5

plug it in to point slope and get: y+8=-13/5(x-3)

slope intercept:

y+8= -13/5x + 39/5

y= -13/5x -1/5

#3: slope = 3/4

point slope form: y-2=3/4(x-3)

slope intercept: y-2=3/4x-9/4 --> y=3/4x-1/4

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Answer:

777.9 meters

Step-by-step explanation:

Notice that the angles of the right triangle are 40 and 50 degrees, with the 500 meter side adjacent to the 50 degree angle. Now, we can set up an equation: cos (50 degrees) = 500 / x. Use a calculator to find that the answer is 777.9.

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3 years ago
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If kenny earns 142% of Benny's Salary, how mucho more does Kenny earn than Benny
Sergeeva-Olga [200]

Let  Benny's salary = $ K

But kenny earns 142% of Benny's Salary

So, Kenny's salary = 142%of K

Kenny's salary =K  \times \frac{142}{100}

Kenny's salary = 1.42K

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% by which Kenny's salary exceeds by Benny's = 42%


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3 years ago
Can someone help me with the working out please its due Tomorrow
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3 years ago
Consider the function on the interval (0, 2π). f(x) = sin x + cos x (a) Find the open intervals on which the function is increas
Annette [7]

Answer:Increasing in x∈(0,π/4)∪(5π/4,2π) decreasing in(π/4,5π/4)

Step-by-step explanation:

given f(x) = sin(x) + cos(x)

f(x) can be rewritten as \sqrt{2} [\frac{sin(x)}{\sqrt{2} }+\frac{cos(x)}{\sqrt{2} }  ]..................(a)\\\\\ \frac{1}{\sqrt{2} } = cos(45) = sin(45)\\\\

Using these result in equation a we get

f(x) = \sqrt{2} [ cos(45)sin(x)+sin(45)cos(x)]\\\\= \sqrt{2} [sin(45+x)]..........(b)

Now we know that for derivative with respect to dependent variable is positive for an increasing function

Differentiating b on both sides with respect to x we get

f '(x) = f '(x)=\sqrt{2}  \frac{dsin(45+x)}{dx}\\ \\f'(x)=\sqrt{2} cos(45+x)\\\\f'(x)>0=>\sqrt{2} cos(45+x)>0

where x∈(0,2π)

we know that cox(x) > 0 for x∈[0,π/2]∪[3π/2,2π]

Thus for cos(π/4+x)>0 we should have

1) π/4 + x < π/2  => x<π/4  => x∈[0,π/4]

2) π/4 + x > 3π/2  => x > 5π/4  => x∈[5π/4,2π]

from conditions 1 and 2 we have  x∈(0,π/4)∪(5π/4,2π)

Thus the function is decreasing in x∈(π/4,5π/4)

5 0
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ILL BRAINLIEST YOU IF YOU PLEASE HELP ME
mr Goodwill [35]

Answer:

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Given 2 sides of a triangle then the third side x is in the range

difference of 2 sides < x < sum of 2 sides , that is

23 - 8 < x < 23 + 8

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3 0
3 years ago
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