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3 years ago

Write the equation of the line in fully simplified slope-intercept form.

Mathematics

1 answer:

masha68 [24]3 years ago

6 0

Answer: y = 6/5x - 1
(WORK SHOWN BELOW)

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A sociologist recorded the estimated life expectancies of women born in Center City. Use the data from women born in 1970 and 20

ANEK [815]

Y = 0.213x – 352.0 <span> represents this linear model shown in the data table.
Plug in the values of x into the equation for a double check.
Let's try 1980.

</span><span>y = 0.213(1980) – 352.0
</span>y = 69.74
which is closest to the 70.1 whereas other options do not satisfy the condition.

6 0

4 years ago

Read 2 more answers

If the area of a circular pool is 300 square yards, what is its radius?

elixir [45]

Answer:

<h2>radius = 9.77 yards</h2>

Step-by-step explanation:

Since the pool is circular

Area of a circle = πr²

where

r is the radius

From the question

Area = 300 square yards

To find the radius substitute the value of the area into the above formula and solve for the radius

That's

300 = πr²

Divide both sides by π

We have

${r}^{2} = \frac{300}{\pi}$

Find the square root of both sides

That's

$r = \sqrt{ \frac{300}{\pi} }$

r = 9.7720502

We have the final answer as

<h3>radius = 9.77 yards</h3>

Hope this helps you

4 0

3 years ago

The spinner has eight spaces of equal size. What is the mathematical probability of the pointer's stopping in the space marked 1

Advocard [28]

Answer:

10/40

Step-by-step explanation:

6 0

3 years ago

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The family of solutions to the differential equation y ′ = −4xy3 is y = 1 √ C + 4x2 . Find the solution that satisfies the initi

slega [8]

Answer:

The correct option is 4

Step-by-step explanation:

The solution is given as

$y(x)=\frac{1}{\sqrt{C+4x^2}}$

Now for the initial condition the value of C is calculated as

$y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(-2)=\frac{1}{\sqrt{C+4(-2)^2}}\\4=\frac{1}{\sqrt{C+4(4)}}\\4=\frac{1}{\sqrt{C+16}}\\16=\frac{1}{C+16}\\C+16=\frac{1}{16}\\C=\frac{1}{16}-16$

So the solution is given as

$y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}$

Simplifying the equation as

$y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1-256+64x^2}{16}}}\\y(x)=\frac{\sqrt{16}}{\sqrt{{1-256+64x^2}}}\\y(x)=\frac{4}{\sqrt{{1+64(x^2-4)}}}$

So the correct option is 4

8 0

3 years ago

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Jon weighs 148 lbs and hopes to gain 2 lbs a week. Matt weighs 193lbs and hopes to lose 1 lb a week. How many weeks until they w

kap26 [50]

It would take 15 weeks and they would meet at 178lbs.

6 0

3 years ago