10 root 2
10^2 + 10^2 = 200
200 is 10 root 2
Answer:
a = 9/2
Step-by-step explanation:
In order for the equation to be true, the value of the scalar multiplier must be ...
15/3 = -10/-2 = 35/7 = 5
So, you're solving ...
(2/3)a + 2 = 5
(2/3)a = 3 . . . . . . subtract 2
a = 9/2 . . . . . . . . multiply by 3/2
Answer:
20%decrease
Step-by-step explanation:
sorry I'm bad at explaining things
Let's start from what we know.

Note that:

(sign of last term will be + when n is even and - when n is odd).
Sum is finite so we can split it into two sums, first

with only positive trems (squares of even numbers) and second

with negative (squares of odd numbers). So:

And now the proof.
1) n is even.
In this case, both

and

have

terms. For example if n=8 then:

Generally, there will be:

Now, calculate our sum:



So in this case we prove, that:

2) n is odd.
Here,

has more terms than

. For example if n=7 then:

So there is

terms in

,

terms in

and:

Now, we can calculate our sum:




We consider all possible n so we prove that: