To divide fractions, you flip the denominator and then multiply it by the numerator.
-6 / 5 x (-25 / 3)
Multiply straight across; the negative cancels out.
150 / 15
This can be reduced to 15, which is its simplest form.
The correlation coefficient of the health research institute data measures the relationship between the age and the years of the smokers
The correlation coefficient is 0.53
<h3>How to calculate the correlation coefficient</h3>
The correlation coefficient (r) is calculated as:
![r = \frac{n(\sum xy) - \sum x \sum y}{\sqrt{[n \sum x^2 - (\sum x)^2][n\sum y^2 - (\sum y)^2}}](https://tex.z-dn.net/?f=r%20%3D%20%5Cfrac%7Bn%28%5Csum%20xy%29%20-%20%5Csum%20x%20%5Csum%20y%7D%7B%5Csqrt%7B%5Bn%20%5Csum%20x%5E2%20-%20%28%5Csum%20x%29%5E2%5D%5Bn%5Csum%20y%5E2%20-%20%28%5Csum%20y%29%5E2%7D%7D)
Using the given parameters, we have:
![r = \frac{20 *8249 - 1257* 116}{\sqrt{[20 * 98823 - 1257^2][20 * 836 - 116^2}}](https://tex.z-dn.net/?f=r%20%3D%20%5Cfrac%7B20%20%2A8249%20-%201257%2A%20116%7D%7B%5Csqrt%7B%5B20%20%2A%2098823%20-%201257%5E2%5D%5B20%20%2A%20836%20-%20116%5E2%7D%7D)
Evaluate the exponents
![r = \frac{20 *8249 - 1257* 116}{\sqrt{[20 * 98823 - 1580049][20 * 836 - 13456}}](https://tex.z-dn.net/?f=r%20%3D%20%5Cfrac%7B20%20%2A8249%20-%201257%2A%20116%7D%7B%5Csqrt%7B%5B20%20%2A%2098823%20-%201580049%5D%5B20%20%2A%20836%20-%2013456%7D%7D)
Evaluate the products
![r = \frac{164980 - 145812}{\sqrt{[1976460 - 1580049][16720 - 13456}}](https://tex.z-dn.net/?f=r%20%3D%20%5Cfrac%7B164980%20-%20145812%7D%7B%5Csqrt%7B%5B1976460%20-%201580049%5D%5B16720%20-%2013456%7D%7D)
Evaluate the differences

Evaluate the product

Evaluate the root

Evaluate the quotient

Hence, the correlation coefficient is 0.53
Read more about correlation coefficient at:
brainly.com/question/1564293
Answer:
HAVE A NICE DAY :)))
Step-by-step explanation:
thank
Ah clever. So you need two formulas.
1) Volume of the marble.
4(pi)r^3/3
= 4(pi)(1.4)^3/3
<span>= 11.49 (approx)
</span>
2) Formula for density.
D = M / V
= 9 / 11.49
= 0.78
0.78 < 1
Therefore the marble will float.