Step-by-step explanation:
x = mass of apples
y = mass of strawberries
z = mass of the box
x = 3y
x + z = 16240
y + z = 6350
let's subtract the second from the first equation
x + z = 16240
- y + z = 6350
-----------------------
x - y + 0 = 9890
using the first identity in that result gives us
3y - y = 9890
2y = 9890
y = 4,945 g
x = 3y = 3×4945 = 14,835 g = the mass of the apples
add 0+1+2+3+4 = 10
divide 10÷5 = 2
add 15+8+3+3+1 = 30
divide 30÷5 = 6
the ratio is 2:6 which simplifies to 1:3 by the means of lates per student. In other words there is one late per 3 students.
Consecutive even integers..x, x + 2, x + 4
x + (x + 2) + (x + 4) = 6216
3x + 6 = 6216
3x = 6216 - 6
3x = 6210
x = 6210/3
x = 2070
x + 2 = 2070 + 2 = 2072
x + 4 = 2070 + 4 = 2074 <===house 3
