Area is 140 and perimeter is 16
Answer:
-2x-2y=-8
-4x-8y=-20
From the 1st eqn
Dividing through by 2
you have
-x-y=-4
Multiply through by -(minus)
x+y=4
x=4-y
Substitute into eqn 2
-4x-8y=-20
-4(4-y)-8y=-20
-16 + 4y - 8y = -20
-4y = -20 +16
-4y = -4
y= 1
Substitute into any of the other eqn's to get x
x= 4-y
x= 4-1
x=3
F(x)=8
3x+2=8
-2 both sides
3x=6
Divide 3 both sides
X=6/3
X=2
Step-by-step explanation:
1. The midpoint formula says the coordinates of the midpoint are the average of the endpoints.
x = (x₁ + x₂) / 2
y = (y₁ + y₂) / 2
I'll do #2 and #3 as examples.
2. x = (-4 + 10) / 2 = 3
y = (6 + -10) / 2 = -2
So the midpoint is (3, -2).
3. x = (-3 + -6.5) / 2 = -4.75
y = (-8 + -4.5) / 2 = -6.25
So the midpoint is (-4.75, -6.25).
Step-by-step explanation:
Area of Rectangle at the top =
Length x Width
Area of Quarter- Circle = 1/4 x Area of Circle
Area of Rectangle at the right = Length x Width
Total Area = Area of 2 Rectangles + Area of Quarter Circle
I will leave the answer in terms of pi as I'm not sure if you need to round off your answer.
