Whats the answer okkkkk

Find the length of a line joining the point ( 4,3 ) and origin .

GalinKa [24]

Answer:

i think you have to count till you get to 4 or 3 then the remaining you plus with the 3

5 0

3 years ago

Read 2 more answers

What is the range of the equation

a_sh-v [17]

The range of the equation is $y>2$

Explanation:

The given equation is $y=2(4)^{x+3}+2$

We need to determine the range of the equation.

<u>Range:</u>

The range of the function is the set of all dependent y - values for which the function is well defined.

Let us simplify the equation.

Thus, we have;

$y=2 \cdot 4^{x+3}+2$

This can be written as $y=2^{1+2(x+3)}+2$

Now, we shall determine the range.

Let us interchange the variables x and y.

Thus, we have;

$x=2^{1+2(y+3)}+2$

Solving for y, we get;

$x-2=2^{1+2(y+3)}$

Applying the log rule, if f(x) = g(x) then $\ln (f(x))=\ln (g(x))$ , then, we get;

$\ln \left(2^{1+2(y+3)}\right)=\ln (x-2)$

Simplifying, we get;

$(1+2(y+3)) \ln (2)=\ln (x-2)$

Dividing both sides by $\ln (2)$ , we have;

$2 y+7=\frac{\ln (x-2)}{\ln (2)}$

Subtracting 7 from both sides of the equation, we have;

$2 y=\frac{\ln (x-2)}{\ln (2)}-7$

Dividing both sides by 2, we get;

$y=\frac{\ln (x-2)-7 \ln (2)}{2 \ln (2)}$

Let us find the positive values for logs.

Thus, we have,;

$x-2>0$

$x>2$

The function domain is $x>2$

By combining the intervals, the range becomes $y>2$

Hence, the range of the equation is $y>2$

7 0

3 years ago

How do i do this pls help me

Delvig [45]

Answer:

$y = \frac{1}{7} x + 7$

Step-by-step explanation:

x-7y = -49

i) move x to the right-hand side and change its sign

-7y = -49-x

ii) change the signs on both sides of the equation

7y = 49+x

iii) divide both sides of the equation by 7

$\frac{7y}{7} = \frac{49}{7} + \frac{x}{7}$

$y = 7 + \frac{1}{7} x$

iv) use the commutative property to reorder the terms

* commutative property: a+b = b+a

$y = \frac{1}{7} x + 7$

3 0

2 years ago

Someone please help me with this and explain it please.

Yuki888 [10]

<h3>Answer: Choice D) $\sqrt{34}, 6, 2\pi, \sqrt{42}$ </h3>

===========================================

Explanation:

Use a calculator to find the decimal form of each of the following below (values are approximate; rounded to 2 decimal places)

2pi = 6.28
sqrt(42) = 6.48
sqrt(34) = 5.83

We see that the order of the decimal values is: 5.83, 6, 6.28, 6.48

So the order of the terms, from smallest to largest, is $\sqrt{34}, 6, 2\pi, \sqrt{42}$

5 0

2 years ago

Which system of equations can be used to find the roots of the equation 4x^5-12x^4+6x=5x^3-2x?

Sveta_85 [38]

$^{(1)}\ \ 4x^5-12x^4+6x=5x^3-2x\ \ ^{(2)}\\\\ \left\{\begin{array}{ccc}y=4x^5-12x^4+6x\ \ \ ^{(1)}\\y=5x^3-2x\ \ \ ^{(2)}\end{array}\right$

Answer: system nr 4.

7 0

2 years ago