What is the greatest common factor of 46a and 50a^2

Use a 95% prediction interval to predict the useful life of a brand A cutting tool when the cutting speed is 45 meters per minu

qwelly [4]

Answer:

<em>The answer resides in the explanation.</em>

<em>Pls rate as brainliest </em>

Step-by-step explanation:

The predicted useful life of a brand A cutting tool when the speed is 45 meters per minute is 1.2 to 5.5 hours.

The predicted useful life of a brand B cutting tool when the speed is 45 meters per minute is 3.4 to 5.4 hours.

The prediction interval for brand A is larger than the prediction interval for brand B because the estimated standard error of y^ is different for the two intervals.

The prediction intervals are both larger than the corresponding confidence intervals.

The standard error for the estimated mean value of y is smaller than the standard error for the predicted value of y.

The predicted useful life of a brand A cutting tool that is operated at 100 meters per minute is -0.59 hours

The actual predicted useful life of a brand A cutting tool when the speed is 100 meters per minute is 0.0 to 2.3 hours.

6 0

3 years ago

Identify the diameter of the circular base created by folding the figure into a right cone. HELP ASAP PLEASE!!

Akimi4 [234]

let's notice something, we have a circle with a radius of 12 and one 90° sector is cut off, so only three 90° sectors of the circle are left shaded, so namely the cone will be using 3/4 of that circle.

think of it as, this shaded area is some piece of paper, and you need to pull it upwards and have the cutoff edges meet, and when that happens, you'll end up with a cone-shaped paper cup, and pour in some punch.

now, once we have pulled up the center of the circle to make our paper cup, there will be a circular base, its diameter not going to be 24, it'll be less, but whatever that base is, we know that is going to have the same circumference as those in the shaded area. Well, what is the circumference of that shaded area?

$\bf \textit{circumference of a circle}\\\\ C=2\pi r~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=12 \end{cases}\implies C=2\pi 12\implies C=24\pi \implies \stackrel{\textit{three quarters of it}}{24\pi \cdot \cfrac{3}{4}} \\\\\\ 6\pi \cdot 3\implies 18\pi$

well then, the circumference of that circle at the bottom will be 18π, so, what is the diameter of a circle with a circumferenc of 18π?

$\bf \textit{circumference of a circle}\\\\ C=2\pi r~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ C=18\pi \end{cases}\implies 18\pi =2\pi r\implies \cfrac{18\pi }{2\pi }=r\implies 9=r \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{\textit{diameter is twice the radius}}{d=18}~\hfill$

3 0

3 years ago

After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modelled by the function C(t)=8(e

Alexxx [7]

Answer:

the maximum concentration of the antibiotic during the first 12 hours is 1.185 $\mu g/mL$ at t= 2 hours.

Step-by-step explanation:

We are given the following information:

After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modeled by the function where the time t is measured in hours and C is measured in $\mu g/mL$

$C(t) = 8(e^{(-0.4t)}-e^{(-0.6t)})$

Thus, we are given the time interval [0,12] for t.

We can apply the first derivative test, to know the absolute maximum value because we have a closed interval for t.
The first derivative test focusing on a particular point. If the function switches or changes from increasing to decreasing at the point, then the function will achieve a highest value at that point.

First, we differentiate C(t) with respect to t, to get,

$\frac{d(C(t))}{dt} = 8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)})$

Equating the first derivative to zero, we get,

$\frac{d(C(t))}{dt} = 0\\\\8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0$

Solving, we get,

$8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0\\\displaystyle\frac{e^{-0.4}}{e^{-0.6}} = \frac{0.6}{0.4}\\\\e^{0.2t} = 1.5\\\\t = \frac{ln(1.5)}{0.2}\\\\t \approx 2$

At t = 0

$C(0) = 8(e^{(0)}-e^{(0)}) = 0$

At t = 2

$C(2) = 8(e^{(-0.8)}-e^{(-1.2)}) = 1.185$

At t = 12

$C(12) = 8(e^{(-4.8)}-e^{(-7.2)}) = 0.059$

Thus, the maximum concentration of the antibiotic during the first 12 hours is 1.185 $\mu g/mL$ at t= 2 hours.

4 0

2 years ago

On 1, I need help, and for 2, is the answer right?

kramer

Answer:

1.A 2.yes

Step-by-step explanation:

PEMDAS

5 0

2 years ago

The ratio of boys to girls in the Science Club is 3.5. If there are 60 girls, how many boys are there?

liubo4ka [24]

Answer:

36 boys

Step-by-step explanation:

3

Please write the ratio as 3:5 or as --------

5

Note that 3 + 5 = 8, so that the fraction of boys in the club is 3/8 and that of girls is 5/8.

How many are in the club altogether? Let this count be represented by c. Then (5/8)c = 60.

Multiplying both sides of this equation by (8/5), to isolate c, we get:

c = (8/5)(60) = 96. Thus, there are 96 Science students altogether.

3/8 of this number are boys. This comes out to (3/8)(96) = 36 boys.

We could also solve this problem in the following manner:

3 b

------ = ------- , where b represents the number of boys.

5 60

Then 5b = 180. Dividing both sides by 5, we get b = 180/5 = 36 boys

3 0

3 years ago