Answer:
Option d num = 50, min = 50, max = 50
Explanation:
Given the code segment:
- boolean isBigger;
- boolean isSmaller;
- boolean inRange;
- if (num < max)
- {
- isSmaller = true;
- }
- else {
- isSmaller = false;
- }
-
- if (num > min)
- {
- isBigger = true;
- }
- else {
- isBigger = false;
- }
-
- if (isBigger == isSmaller) {
- inRange = true;
- } else {
- inRange = false;
- }
If we have num = 50, min = 50 , max = 50, the condition num < max will be evaluated to false and therefore isSmaller is set to false.
The condition num > min will be evaluated to false as well and therefore isBigger is set to false.
Since isSmaller and isBigger are both false and therefore isBigger == isSmaller will be evaluated to true and set the inRange = true. This has violated the statement that if the integer value num is greater than min value and less than max value, then only set inRange to true. This is because num = 50 is neither greater than min nor less than max, it is supposedly not in range according to the original intention of the code design.
Answer:
Hello your question is incomplete below is the complete question
The following questions refer to this data segment (in x86 assembler language):
.data
var1 db 10h,20h
var2 dw 1020h
var3 db '4'
var4 db '56'
var5 db '789','$'
How many bytes will have been written to the standard output device after all these instructions have been executed?
mov dx, offset var3
mov ah, 9
int 21h
Answer : 4 bytes
Explanation:
(in x86 assembler language) The number of bytes that will have been written to the standard output device after the instructions listed have been executed is : 4 bytes
-31 or 21- 50 it may also carry -31
B the need to import items for any technology to really work
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