What's the circumference of a

Which pair of functions are inverses?

sashaice [31]

Answer:

just need

Step-by-step explanation:

free points

7 0

3 years ago

Find the coordinates using A prime and all that!! I hope you know what I mean please help!!!! ASAPP

Ierofanga [76]

Answer:

See picture for explanation.

Step-by-step explanation:

6 0

3 years ago

Isaac is making sandwiches for a group of friends. He needs 3 ounces of meat for each sandwich.

lidiya [134]

Answer:

Part A: x=3

Part B: 6oz

3x=18

Step-by-step explanation:

Part A-

So, he needs 3 oz for each sandwich.

This gives us 3 for the equation.

The question says that we need an equation for this.

If we need an equation, we could write something like

x=3

There's really not anything else that we could write here.

Part B-

We now have something that we need to write.

He has 18 oz for sandwiches.

Each sandwich needs 3 oz.

So, we can write something like 3x=18

Then we could solve the equation by dividing both sides by 3.

This will leave us with x=6

Hope this works!

6 0

3 years ago

Read 2 more answers

Find the extreme values of the function f(x, y) = 4x2 + 6y2 on the circle x2 + y2 = 1.

julia-pushkina [17]

Answer with Step-by-step explanation:

We are given that

$f(x,y)=4x^2+6y^2$

Let g(x,y)= $x^2+y^2=1$

We have to find the extreme values of the given function

$\nabla f(x,y)$

$\nabla g(x,y)=$

Using Lagrange multipliers

$\nabla f(x,y)=\lambda \nabla g(x,y)$

$f_x=\lambda g_x$

$8x=\lambda 2x$

Possible value x=0 or $\lambda=4$

If x=0 then substitute the value in g(x,y)

Then, we get $y=\pm 1$

$f_y=\lambda g_y$

$12y=\lambda 2y$

If $\lambda=4$ and substitute in the equation

Then , we get possible value of y=0

When y=0 substitute in g(x,y) then we get

$x=\pm 1$

Hence, function has possible extreme values at points (0,1),(0,-1), (1,0) and (-1,0).

$f(0,1)=6$

$f(0,-1)=6$

$f(1,0)=4$

$f(-1,0)=4$

Therefore, the maximum value of f on the circle $x^2+y^2=1$ is $f(0,\pm1)=6$ and minimum value of $f(\pm1,0)=4$

7 0

3 years ago

PLEASE HELP!! A car manufacturer does performance tests on its cars. During one test, a car starts from rest, and accelerates at

slega [8]

Answer:

0 ≤ t ≤ 25
16.348 seconds
310.0 meters

Step-by-step explanation:

a) Since these are production vehicles, we don't expect their top speed to be more than about 70 m/s, so the distance functions probably lose their validity after t = 25. Of course, t < 0 has no meaning in this case, so the suitable domain is about ...

0 ≤ t ≤ 25

Note that the domain for the second car would be 3 ≤ t ≤ 25.

__

b) The graph of this system shows the cars will both have driven the same distance after 16.348 seconds.

__

c) At that time, the cars will have driven 310.0 meters.

_____

<em>Non-graphical solution</em>

If you like, you can solve the equation for t:

d1 = d2

1.16t^2 = 1.74(t -3)^2

0 = 0.58t^2 -10.44t +15.66

t = (10.44 +√(10.44^2 -4(0.58)(15.66)))/(2(0.58)) = (10.44+8.524)/1.16

t = 16.348 . . . . time in seconds the cars are at the same distance

That distance is found using either equation for distance:

1.16t^2 = 1.16(16.348^2) = 310.036 . . . meters

6 0

4 years ago