Answer:
Step-by-step explanation:
Given is a function
Average slope of this function is change of f(x) in (-2,6)/change of x in (-2,6)
= 
By mean value theorem there exists a c such that f'(c) = -18
i.e. 
Using quadratic formula
x = 2.61, -1.277
Out of these only 2.61 lies in the given interval
c = 2.61
Answer:
help
Step-by-step explanation:
I think that the answer is C
Using <span>Descartes' rule of signs.
There are 4 changes of signs of coefficients:
+ to - (+x^6-x^5)
- to + (-x^4+4x^3)
+ to - (+4x^3-12x^2)
- to + (-12x^2+12)
Therefore, there are 4,2 or 0 positive roots </span><span><span>at most</span>. So it must be the third answer.
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