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WITCHER [35]
2 years ago
13

Find the geometric mean between 18 and 7. Write your answer in radical form.

Mathematics
1 answer:
solmaris [256]2 years ago
3 0

Answer: Choice A

Work Shown:

m = \text{geometric mean of x and y}\\\\m = \sqrt{x*y}\\\\m = \sqrt{18*7}\\\\m = \sqrt{9*2*7}\\\\m = \sqrt{9}*\sqrt{2*7}\\\\m = 3\sqrt{14}\\\\

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What's bigger 3/4 or 9/12
pashok25 [27]
Change the common denominator so 3/4 ---> 9/12 
3/4 and 9/12 are equal

Hope this helps!!!
3 0
3 years ago
Read 2 more answers
Maya shaved her head and then began letting her hair grow. She represents the length \ellℓell of her hair, in centimeters, mmm m
Zarrin [17]

Answer:

Maya's hair grows at the rate of 1.25cm per month

Step-by-step explanation:

After Maya shaved her hair,

She monitored the growth and recorded the length of the hair monthly in centimeters using the equation ell=1.25mℓ=1.25mell

Therefore, since the length of hair is recorded on a monthly basis, 1.25 in the equation refers to the rate of growth as measured by the length of hair per month.

4 0
3 years ago
Straight leg jeans are 20% off at Kohls this week. How much will you pay for 4 pairs if the regular price is $59.99?
ankoles [38]
20% of 59.99 is 11.998 so 11.99. 59.99 - 11.99 = 48. 48x4 is 192
192$
5 0
3 years ago
Help me please!
masya89 [10]

Answer:

951.15 ltr

Step-by-step explanation:

first you convert inch into cm just to make things easier

1 inch = 2.54cm

so,

radius(r)= 24 inch = 24×2.54= 60.96cm≈ 61 cm

then calculate the volume of the sphere

i.e.

V = 4/3(πr³)= 4/3×22/7× 61³= 951158.47 cm³

Now that we have volume

we know that,

1 ltr = 1000cm³

sooo,

  • x ltr= 951158.47÷1000= 951. 15 ltr

8 0
3 years ago
Four pounds of apples cost $5. Eght pounds of apples cost $10. If the total cost of apples, y varies directly with the
dlinn [17]
Well the cost of the apples can be found by dividing the price by the amount bought. ($5/4 or $10/8 = $1.25/lb). If you want to find the amount for 6 pounds just multiply it by the individual cost (6x$1.25= $7.50)
5 0
3 years ago
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