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3 years ago

Divide. (6.496×10−6)÷(2.8×105) Express your answer in scientific notation. Enter your answer in the boxes.

Mathematics

1 answer:

ss7ja [257]3 years ago

6 0

we have been asked to perform $(6.496*10^{-6})\div (2.8*10^5)$

The given expression can be written as

$\frac{(6.496*10^{-6})}{2.8*10^5}$

Now it can be re-written as below

$=\frac {(6.496*10^{-6})}{2.8*10^5}=\frac{6.496}{2.8}*\frac{10^{-6}}{10^5}\\ \\ \text{Now using the exponent rule } \\ \\ \frac{a^m}{a^n}=a^{m-n}\\ \\ \text{we can re-write as below}\\ \\ \frac{6.496}{2.8}*\frac{10^{-6}}{10^5}= \frac{6.496}{2.8}*10^{-6-5}= \frac{6.496}{2.8}*10^{-11}\\ \\ \text{Now divide we get}\\ \\ =2.32*10^{-11}$

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MArishka [77]

2^4x-2^3x-3

2^3=2x2x2
Which equals 8

3 0

3 years ago

True or false: Every sequence is either arithmetic or geometric. If this is true, explain. If false,

tiny-mole [99]

In an arithmetic sequence, the difference between consecutive terms is constant. In formulas, there exists a number $r$ such that

$a_{n+1}-a_n=r\quad \forall n\geq 1$

In an geometric sequence, the ratio between consecutive terms is constant. In formulas, there exists a number $r$ such that

$\dfrac{a_{n+1}}{a_n}=r\quad \forall n\geq 1$

So, there exists infinite sequences that are not arithmetic nor geometric. Simply choose a sequence where neither the difference nor the ratio between consecutive terms is constant.

For example, any sequence starting with

$1, 15, -3,\ldots$

Won't be arithmetic nor geometric. It's not arithmetic (no matter how you continue it, indefinitely), because the difference between the first two numbers is 14, and between the second and the third is -18, and thus it's not constant. It's not geometric either, because the ratio between the first two numbers is 15, and between the second and the third is -1/5, and thus it's not constant.

5 0

3 years ago

Triangles O N M and S R Q are shown. Angles O N M and S R Q are congruent. The length of side N M is 10 and the length of side S

valina [46]

Answer:

Option C.

Step-by-step explanation:

In △ONM and △SRQ,

$\angle ONM\cong \angle SRQ$

$NM=10$

$SR=20$

$NO=8$

$QR=x$

We need to find the value of x that will make △ONM similar to △SRQ by the SAS similarity theorem.

According to SAS similarity theorem, two triangle are similar if two corresponding sides in both triangles are proportional and the included angle in both are congruent.

It is given that $\angle ONM\cong \angle SRQ$ . So, both triangles are similar by SAS if

$\dfrac{NO}{NM}=\dfrac{SR}{QR}$